Identify the reactants in the following equation.

An object has a velocity of 8m/s and a kinetic energy of 480 j what is the mass of the object

MariettaO [177]

Kinetic energy=Ek
Ek=(1/2)mv²
Ek=480 J
v=8 m/s
mass=?

Ek=(1/2)mv²
480 J=(1/2)m(8 m/s)²
480 J=(32 m²/s²) m
m=(480 J)/(32 m²/s²)=15 kg

answer: the mass of the object is 15 kilograms.

3 0

3 years ago

Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following

bearhunter [10]

Answer:

$210.7~g~MgCO_3$

Explanation:

We have to start with the reaction:

$MgCO_3~->~MgO~+~CO_2$

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the number of moles that we have in the 110.0 g of carbon dioxide, to this, we have to know the atomic mass of each atom:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the molar mass of carbon dioxide:

$(12*1)+(16*2)=44~g/mol$

In other words: $1~mol~CO_2=~44~g~CO_2$ . With this in mind, we can calculate the moles:

$110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2$

Now, the molar ratio between carbon dioxide and magnesium carbonate is 1:1, so:

$2.5~mol~CO_2=2.5~mol~MgCO_3$

With the molar mass of $MgCO_3$ ( $(23.3*1)+(12*1)+(16*3)=84.3~g/mol$ . With this in mind, we can calculate the grams of magnesium carbonate:

$2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3$

I hope it helps!

8 0

3 years ago

If you stirred some sugar in water the sugar would disappear but the water would taste sweet. This is because __________ change

olganol [36]

a hopefully this is helpful

7 0

3 years ago

A highway engineer is researching de-icing compounds for clearing ice from streets in winter. She wants a compound that has +2 i

wolverine [178]

Magnesium combined with chlorine.

How?

Look at the question .Compound has -1 charge in it .Hence it contains Halogen.
Looking at the options Option B and C contain Iodine and chlorine i.e halogens .

Now come to metals side.

Potassium has valency 1(Look the Electronic configuration below)

$\\ \sf\longmapsto 1s^22s^22p^63s^23p^64s^1$

Hence it will contain +1 charge which is omitted directly .

Now come to option C.

Magnesium has charge +2(Look at EC below

$\\ \sf\longmapsto 1s^22s^22p^63s^2$

Hence the compound formed is given by

$\\ \sf\longmapsto MgCl_2$

Hence option C is correct.

3 0

3 years ago

Identify the major force between molecules of pentane. dispersion dipole-dipole hydrogen bonding ion-dipole ion-ion

Lyrx [107]

It wouldn’t be hydrogen bonding because hydrogen bonding takes place with highly electronegative elements like N,O & F being the most electronegative. It’s not ion - dipole because there is no ion present. So I’m sure it is dispersion

5 0

3 years ago

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