Answer:
New Gas volume (V2) = 5.86 L
Explanation:
Given:
Gas volume (V1) = 2.93 L
Temperature (T1) = 20°Celsius
After Increasing temperature:
New Temperature (T2) = 40°Celsius
Find:
New Gas volume (V2) = ?
Computation:
According to Charles' gas Law:
⇒ Gas volume (V1) / Temperature (T1) = New Gas volume (V2) / New Temperature (T2)
⇒ 2.93 L / 20°Celsius = New Gas volume (V2) / 40°Celsius
⇒ New Gas volume (V2) = 5.86 L
<em>Five household items that </em><em>contain</em><em> the same chemicals as cigarettes :</em><em>-</em>
- <em>Perfume</em>
- <em>Household</em><em> </em><em>cleaning</em><em> </em><em>products</em>
- <em>Beauty</em><em> </em><em>Products</em>
- <em>Sunscreen</em>
- <em>Water</em><em> </em><em>bottles</em>
<em>They</em><em> </em><em>contain</em><em> </em><em>toxic</em><em> </em><em>substances</em><em>!</em>
<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>!</em>
Answer:The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound, C5H10O2, exhibits strong, broad absorption across the 2500-3200 cm^1 region and an intense absorption at 1715 cm'^-1. Relative absorption intensity: (s)=strong, (m)-medium, (w) weak. What functional class(cs) docs the compound belong to List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm^1. The functional class(es) of thla compound is(are) alkane (List only if no other functional class applies.) alkene terminal alkyne internal alkyne arene alcohol ether amine aldehyde or ketone carboxylic acid ester nitr
C is the answer To the question
Answer:
Kp = 13.3
Explanation:
Partition coefficient is used to extract or purify a solute from a solvent selectively to avoid interference from other substances. The formula is:
Kp = Concentration of solute in organic solvent / Concentration of solute in H₂O
As the CH₂Cl₂ is containing 31mg, water is containing 4mg. Replacing in the formula:
Kp = (31mg/7mL) / (4mg/12mL)
<h3>Kp = 13.3</h3>
