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Elan Coil [88]
3 years ago
5

Zeke is on spring break. He lives in a cold climate, so he decides to drive to a warmer climate. Before he leaves for his vacati

on, he checks the air pressure in his tires. After a few days of driving, he reaches his destination and stops for more fuel. While fueling up, he checks his tires' air pressure again and notices it has increased. Which option best explains the change in the air pressure of Zeke's tires? Select all that apply.
The warmer temperatures at Zeke's destination caused the volume of air in his tires to increase.
The warmer temperatures at Zeke's destination caused the pressure in his tires to spread out equally.
The warmer temperatures at Zeke's destination caused the pressure in his tires to increase.
The warmer temperatures at Zeke's destination caused the volume of air in his tires to decrease.
Chemistry
2 answers:
STatiana [176]3 years ago
4 0

The warmer temperatures at Zeke's destination caused the volume of air in his tires to increase.

arsen [322]3 years ago
4 0

Answer: Option (1)

Explanation: The air pressure and the temperature is directly proportional to each other. This means that, higher the temperature, higher is the air pressure, and lesser the temperature, lesser is the air pressure.

According to the given condition, when Zeke travels from a colder climate to a comparatively warmer climate, the air molecules gets get heated up, and become active, as a result of which, the air pressure in the tyre increases by a certain amount.

Thus the correct answer is option (1).

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A certain first-order reaction is 27.5 percent complete in 8.90 min at 25°C. What is its rate constant?
jeyben [28]

Answer:

k= 0.145min^{-1}

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us remember that the first-order kinetics is given by:

ln(A/A_0)=-kt

Whereas the 27.5% complete means A/Ao=0.275, and thus, we solve for the rate constant as follows:

k=\frac{ln(A/A_0)}{-t}

Then, we plug in the variables to obtain:

k=\frac{ln(0.275)}{-8.90min}\\\\k= 0.145min^{-1}

Regards!

4 0
3 years ago
Which term best describes the stored energy based on the position or chemical composition of an object?
Bad White [126]
Stored energy is described as potential energy
5 0
3 years ago
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Draw the major byproduct of the reaction (not the minor species discussed in q2b). At which stage did you remove it from your sa
givi [52]

You need to do something like that your self so sorry can help.

3 0
3 years ago
What is the mass of a sample of metal that is heated from 58.8°C to 88.9°C with a
Vadim26 [7]

Answer:

\boxed {\boxed {\sf 333 \ grams}}

Explanation:

We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.

Q= mc \Delta T

The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

  • ΔT= final temperature - initial temperature

The sample was heated <em>from </em> 58.8 degrees Celsius to 88.9 degrees Celsius.

  • ΔT= 88.9 °C - 58.8 °C = 30.1 °C

Now we know three variables:

  • Q= 4500.0 J
  • c= 0.4494 J/g°C
  • ΔT = 30.1 °C

Substitute these values into the formula.

4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)

Multiply on the right side of the equation. The units of degrees Celsius cancel.

4500.0 \ J = m (13.52694 J/g)

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}

The units of Joules cancel.

\frac {4500.0 \ J }{13.52694 J/g}= m

332.6694729 \ g =m

The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.

333 \ g \approx m

The mass of the sample of metal is approximately <u>333 grams.</u>

8 0
3 years ago
List the compounds in decreasing boiling point order. ch3ch2ch3 ar ch3cn
leva [86]

The boiling point depends on the strength of the intermolecular forces holding the molecules together. Greater the force, higher is the boiling point.

The intermolecular force increases in the order shown below:

ion-ion > H-bonding > dipole-dipole > London dispersion

CH3CN is a polar molecule with strong dipole-dipole forces

CH3CH2CH3 is non-polar held by london dispersion

Ar exist as a gas. It will have a lowest boiling point

Thus the order of decreasing b.pt is:

CH3CN > CH3CH2CH3 > Ar

6 0
3 years ago
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