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Elan Coil [88]
3 years ago
5

Zeke is on spring break. He lives in a cold climate, so he decides to drive to a warmer climate. Before he leaves for his vacati

on, he checks the air pressure in his tires. After a few days of driving, he reaches his destination and stops for more fuel. While fueling up, he checks his tires' air pressure again and notices it has increased. Which option best explains the change in the air pressure of Zeke's tires? Select all that apply.
The warmer temperatures at Zeke's destination caused the volume of air in his tires to increase.
The warmer temperatures at Zeke's destination caused the pressure in his tires to spread out equally.
The warmer temperatures at Zeke's destination caused the pressure in his tires to increase.
The warmer temperatures at Zeke's destination caused the volume of air in his tires to decrease.
Chemistry
2 answers:
STatiana [176]3 years ago
4 0

The warmer temperatures at Zeke's destination caused the volume of air in his tires to increase.

arsen [322]3 years ago
4 0

Answer: Option (1)

Explanation: The air pressure and the temperature is directly proportional to each other. This means that, higher the temperature, higher is the air pressure, and lesser the temperature, lesser is the air pressure.

According to the given condition, when Zeke travels from a colder climate to a comparatively warmer climate, the air molecules gets get heated up, and become active, as a result of which, the air pressure in the tyre increases by a certain amount.

Thus the correct answer is option (1).

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Need help !!!!! ASAP
Julli [10]
<h2>Hello!</h2>

The answer is:

The new volume will be 1 L.

V_{2}=1L

<h2>Why?</h2>

To solve the problem, since we are given the volume and the first and the second pressure, to calculate the new volume, we need to assume that the temperature is constant.

To solve this problem, we need to use Boyle's Law. Boyle's Law establishes when the temperature is kept constant, the pressure and the volume will be proportional.

Boyle's Law equation is:

P_{1}V_{1}=P_{2}V_{2}

So, we are given the information:

V_{1}=2L\\P_{1}=50kPa\\P_{2}=100kPa

Then, isolating the new volume and substituting into the equation, we have:

P_{1}V_{1}=P_{2}V_{2}

V_{2}=\frac{P_{1}V_{1}}{P_{2}}

V_{2}=\frac{50kPa*2L}{100kPa}=1L

Hence, the new volume will be 1 L.

V_{2}=1L

Have a nice day!

4 0
3 years ago
Write a balanced chemical equation for the reaction that occurs when heptane, C7H16(l) , burns in air.
Pavlova-9 [17]
Start with Unbalanced Equation and balance it, so...
C7H16+O2--->CO2+H2O
There are 7 C atoms on the left-hand side, so we need 7 C atoms on the right-hand side. Add a 7 in front of the CO2...7CO2+H2O on right side now.
We have fixed 16 H atoms on the left-hand side, so we need 16 H atoms on the right-hand side. Add an 8 in front of H2O to make 16 (8x2)...7CO2+8H2O on right side now.
There are 22 O atoms on the right-hand side: 14 from the CO2 and 8 from the H2O. Add an 11 in front of the O2 on the left side to make 22 (11x2).
Every formula now has a fixed coefficient. You should have a balanced equation of...
C7H16+11O2--->7CO2+8H2O
8 0
3 years ago
Convert ethene to propanol​
klemol [59]

Answer:

The dehydration of ethanol Highlights Reductive Hydroformylation of ethene to propanol with homogeneous rhodium catalysts. Propane can be oxidized to propanol, and then dehydrated to form propene.

Explanation:

Always be happy!

:)

7 0
3 years ago
Consider the first-order reaction described by the equation At a certain temperature, the rate constant for this reaction is 5.8
zubka84 [21]

<u>Answer:</u> The half life of the reaction is 1190.7 seconds

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

k = rate constant of the reaction = 5.82\times 10^{-4}s^{-1}

t_{1/2} = half life of the reaction = ?

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{5.82\times 10^{-4}s^{-1}}=1190.7s

Hence, the half life of the reaction is 1190.7 seconds

8 0
3 years ago
Can anybody check my answer?
anzhelika [568]

Answer:

\boxed{\text{25. 20 L; 26. 49 K}}

Explanation:

25. Boyle's Law

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p_{1}V_{1} = p_{2}V_{2}

Data:

\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}

Calculations:

\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}

26. Ideal Gas Law

We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.

pV = nRT

Data:  

p = 101.3 kPa

V = 20 L

n = 5 mol

R = 8.314 kPa·L·K⁻¹mol⁻¹

Calculation:

101.3 × 20 = 5 ×  8.314 × T

2026 = 41.57T

T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}

6 0
3 years ago
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