The first thing we must do for this case is the sum of forces in a horizontal direction.
We have then:
Substituting values we have:
From here, we clear the mass of the object:
We now look for the weight of the object.
Where,
g: acceleration of gravity (9.8 m/s^2)
Substituting values:
Answer:
the weight of the object is:
option 4
The speed of the 0.8 kg ball immediately after collision is 0.625 m/s in opposite direction to the stationary ball.
The given parameters;
Let the final velocity of the 0.8 kg ball immediately after collision = v₁
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(0.8 x 2.5) + (2.5 x 0) = (0.8)v₁ + 2.5(1)
2 = 2.5 + (0.8)v₁
-0.5 = (0.8)v₁
Thus, the speed of the 0.8 kg ball immediately after collision is 0.625 m/s in opposite direction to the stationary ball.
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<u>Explanation:</u>
Reaction quotient is defined as the ratio of the concentration of the products and reactants of a reaction at any point of time with respect to some unit. It is represented by the symbol <em>Q</em>.
The ratio of the concentration of products and reactants of a reaction in equilibrium with respect to some unit is said to be equilibrium constant expression. It is represented by the symbol <em>K</em>.
The relationship between Gibbs free energy change and reaction quotient of the reaction is:
......(1)
where,
= Gibbs free energy change
= Standard Gibbs free energy change
R = Gas constant
T = Temperature
At equilibrium, the free energy change of the reaction becomes 0 and standard Gibbs free energy change can be related to the equilibrium constant by the equation:
...(2)
Answer:
(a). The height of the cliff is 41.67 m.
(b). The maximum height of the ball is 41.67 m
(c). The ball's impact speed is 16.52 m/s.
Explanation:
Given that,
Speed = 33 m/s
Angle = 60°
Time = 3.0 sec
(a). We need to calculate the height of the cliff
Using equation of motion
Put the value into the formula
(b). We need to calculate the maximum height of the ball
Using formula of height
Put the value into the formula
(c). We need to calculate the vertical component of velocity of ball
Using equation of motion
Put the value into the formula
We need to calculate the horizontal component of velocity of ball
Using formula of velocity
Put the value into the formula
We need to calculate the ball's impact speed
Using formula of velocity
Put the value into the formula
Hence, (a). The height of the cliff is 41.67 m.
(b). The maximum height of the ball is 41.67 m
(c). The ball's impact speed is 16.52 m/s.