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2 years ago

What is electrostatic force?

Physics

1 answer:

zalisa [80]2 years ago

5 0

"Electrostatic forces are attractive or repulsive forces between particles that are caused by their electric charges."

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Two balls are placed near one another and hang down, as shown below.

Delicious77 [7]

Answer:

<h2>a- neither ball has a charge</h2>

Explanation:

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2 years ago

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What is the speed of a cheetah that travels 176.4 meters in 4.5 seconds?

Ugo [173]

Answer:

$\boxed{ \bold{ \boxed{ \sf{39.2 \: m/ {s} \: }}}}$

Explanation:

Given,

Distance travelled ( d ) = 176.4 meters

Time taken ( t ) = 4.5 seconds

Finding the speed of a cheetah

Speed $\sf{ = \frac{distance \: travelled}{time \: taken} }$

$\sf{ = \frac{176.4}{4.5} }$

$\sf{ = 39.2 \: m/ {s} \: }$

------------------------------------------------------------------------

Let's learn about Speed  :

Suppose a body moves 20 m in 2 seconds, either on a curved path or on a straight path. So , 10 m is the distance travelled by the body in each second which can be written as 10 m/s. This is called speed of the body. Thus, Speed is defined as the distance travelled per unit time. It is the rate of distance travelled by a body.

Mathematically,

$\boxed{ \bold{ \sf{speed = \frac{distance \: travelled}{time \: taken} }}}$

In SI system, the unit of distance is metre and time is second. Thus , the SI unit is speed is m/s.

Hope I helped!

Best regards!!

8 0

2 years ago

Tom drives on a highway and never changes his speed for the whole journey. He drives for 300 miles and it takes him 5 hours. Wha

Nata [24]

Answer:

QESARDFRGTSRTATFREVERSRvrvqwqv

Explanation:

vfqfvcafbraf w rfdsd AEWvd a

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2 years ago

How much weight can a 2x2 support horizontally?

Charra [1.4K]

I got 35 lbs because your doubling the support

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2 years ago

A charge q1 of -5.00X10^-9 C and a charge q2 of -2.00X10^-9 C are separated by a distance of 40.0 cm. Find the equilibrium posit

Alex73 [517]

Answer:

The equilibrium position for the third charge is 69.28 cm

Explanation:

Given;

q₁ = -5.00 x 10⁻⁹ C

q₂ = -2.00 x 10⁻⁹ C

q₃ = 15.00 x 10⁻⁹ C

distance between q₁ and q₂ = 40.0 cm = 0.4 m

(-q₁)--------------------------------------(-q₂)---------------------------------(+q₃)

At equilibrium the repulsive force between q₁ and q₂ must be equal to attractive force between q₂ and q₃

According to Coulomb's law, repulsive or attractive force between charges is calculated as;

$F = \frac{Kq_1q_2}{r_1^2} = \frac{Kq_2q_3}{r_2^2}$

where;

F is repulsive or attractive force between charges

K is Coulomb's constant = 8.99 x 10⁹ Nm²/c²

r₁ is the distance between q₁ and q₂

q₁, q₂ and q₃ are the charge

distance between q₂ and q₃, r₂ is calculated as;

$\frac{Kq_1q_2}{r_1^2} = \frac{Kq_2q_3}{r_2^2}\\\\\frac{q_1q_2}{r_1^2} = \frac{q_2q_3}{r_2^2}\\\\r_2^2= \frac{r_1^2q_2q_3}{q_1q_2}\\\\r_2^2= \frac{r_1^2q_3}{q_1} = \frac{0.4^2*15*10^{-9}}{5*10^{-9}} = 0.48\\\\r_2 = \sqrt{0.48} = 0.6928 \ m$

Therefore, the equilibrium position for the third charge is 69.28 cm

3 0

2 years ago

What is electrostatic force? ​

What is electrostatic force?