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Akimi4 [234]
3 years ago
6

Is ADa is civil rights

Physics
1 answer:
Travka [436]3 years ago
5 0

Yes the ADa is a civil right law.

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A long, nonconducting cylinder (radius = 6.0 mm) has a nonuniform volume charge density given by αr2, where α = 6.2 mC/m5 and r
erastovalidia [21]

Answer: 2.80 N/C

Explanation: In order to calculate the electric firld inside the solid cylinder

non conductor we have to use the Gaussian law,

∫E.ds=Q inside/ε0

E*2πrL=ρ Volume of the Gaussian surface/ε0

E*2πrL= a*r^2 π* r^2* L/ε0

E=a*r^3/(2*ε0)

E=6.2 * (0.002)^3/ (2*8.85*10^-12)= 2.80 N/C

5 0
4 years ago
Pls i need this now
dmitriy555 [2]
A

Because all living things have living matter
6 0
3 years ago
A phone cord is 2.28 m long. The cord has a mass of 0.2 kg. A transverse wave pulse is produced by plucking one end of the taut
Debora [2.8K]

The characteristics of the speed of the traveling waves allows to find the result for the tension in the string is:  

         T = 10 N

The speed of a wave on a string is given by the relationship.

      v =\sqrt{\frac{T}{\mu } }

Where   v es the velocty, t is the tension ang μ is the lineal density.

They indicate that the length of the string is L = 2.28 m and the pulse makes 4 trips in a time of t = 0.849 s, since the speed of the pulse in the string is constant, we can use the uniform motion ratio, where the distance traveled e 4 L

           v = \frac{d}{t}  

           v = \frac{4 L}{t}  

           v = \frac{4 \ 2.28 }{0.849}  

            v = 10.7  m / s

Let's find the linear density of the string, which is the length of the mass divided by its mass.

            μ = \frac{m}{L}  

            \mu = \frac{0.2}{2.28}  

            μ = 8.77 10⁻² kg / m

The tension is:

        T = v² μ

Let's calculate

        T = 10.7²  8.77 10⁻²

        T = 1 0 N

In conclusion using the characteristics of the velocity of the traveling waves we can find the result for the tension in the string is:

         T = 10 N

Learn more here:  brainly.com/question/12545155

7 0
3 years ago
What minimum heat is needed to bring 150 g of water at 20 ∘c to the boiling point and completely boil it away? the specific heat
AnnZ [28]

Try this solution:

if given m=0.15 kg; t₁=20 °C; t₂=100 °C; c=4190 J/(kg*C); q=226*10⁴ J/kg., then


Q=Q₁+Q₂,

where Q₁=cm(t₂-t₁) and Q₂=q*m.

Finally,

Q=cm(t₂-t₁)+qm;

Q=4190*0.15*80+2240000*0.15=386280 J=<u>386.28 kJ</u>.

4 0
4 years ago
ppose that you hold a vibrating 340 Hz tuning fork near a guitar string that is vibrating at 350 Hz. What you hear is?
galben [10]

Answer:

A beat with the frequency of 10Hz.

Explanation:

The frequencies from the tuning fork and guitar will cancel each other.

The frequency of tuning fork = 340Hz

The frequency of guitar string= 350Hz

The offset = 350Hz - 340Hz = 10Hz

A 10Hz frequency sound is still heard.

3 0
3 years ago
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