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I am Lyosha [343]
3 years ago
9

Is C3N2H4 a organic compound

Chemistry
2 answers:
KengaRu [80]3 years ago
8 0

Organic compounds and inorganic compounds form the basis of chemistry. ... Also, nearly all organic compounds contain carbon-hydrogen or C-H bonds. Note, containing carbon is not sufficient for a compound to be considered organic! Look for both carbon and hydrogen.Jun 1, 2018

Yakvenalex [24]3 years ago
5 0

<u>Answer:</u> Yes, this is a organic compound.

<u>Explanation:</u>

Organic compound is defined as the compound in which covalent bond is present between hydrogen and carbon atoms. They are also known as hydrocarbons. <u>For Example:</u> CH_4,CH_3OH are organic compounds but CO_2,H_2O are not organic compounds.

We are given a chemical compound which is C_3N_2H_4

In this compound, a covalent bond is present between carbon and hydrogen atoms. Thus, it is considered as an organic compound.

Hence, yes, this is a organic compound.

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A 0.4021-g sample of a purified organic acid was dissolved in water and titrated potentiometrically. A plot of the data revealed
Archy [21]

Answer:

The molar mass of the acid is 167.5 g/mol

Explanation:

A 0.4021-g sample of a purified organic acid was dissolved in water and titrated potentiometrically. A plot of the data revealed a single end point after 19.31 mL of 0.1243 M NaOH had been introduced. Calculate the molecular mass of the acid.

Step 1: Data given

Mass of the sample of a purified organic acid = 0.4021 grams

Molarity = 0.1243 M

Volume needed to reach the end point = 19.1 mL = 0.01931 L

Step 2: Calculate the number of moles NaOH

Moles NaOH = molarity NaOH  * volume

Moles NaOH = 0.1243 M * 0.01931 L

Moles NaOH = 0.00240 moles

Step 3: Calculate moles of the acid

We'll need 0.00240 moles of acid to neutralize 0.00240 moles of NaOH ( it's a single end point)

Moles acid = 0.00240 moles

Step 4: Calculate molar mass of the acid

Molar mass = mass / moles

Molar mass = 0.4021 grams / 0.00240 moles

Molar mass = 167.5 g/mol

The molar mass of the acid is 167.5 g/mol

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Answer:

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