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ElenaW [278]
3 years ago
5

The molar mass of magnesium fluoride is?

Chemistry
1 answer:
Viktor [21]3 years ago
8 0
The chemical formula for magnesium fluoride would be MgF2 (the 2 is subscript but I cannot type that)

Mm=Molar mass

Mm(Mg)= 24.31g/mol
Mm(F) = 19.00g/mol

Mm(MgF2) = 2(19.00) + 24.31
Mm(MgF2) = 62.31g/mol
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2. A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine:2HI (g) H2(g)
Deffense [45]

Answer:

The value of Kp at this temperature is 7.44*10⁻³

Explanation:

Chemical equilibrium is established when there are two opposite reactions that take place simultaneously at the same speed.

For the general chemical equation for a homogeneous gas phase system:

aA + bB ⇔ cC + dD

where a, b, c and d are the stoichiometric coefficients of compounds A, B, C and D, the equilibrium constant Kp is determined by the following expression:

Kp=\frac{P_{C} ^{c} *P_{D} ^{d} }{P_{A} ^{a} *P_{B} ^{b} }

Where Px is the partial pressure of each of the components once equilibrium has been reached and they are expressed in atmospheres. The equilibrium constant Kp depends solely on temperature and is dimensionless.

In the case of the reaction:

2 HI (g) ⇔ H₂ (g) + I₂ (g)

the equilibrium constant Kp is determined by the following expression:

Kp=\frac{P_{H_{2} } *P_{I_{2} } }{P_{HI} ^{2} }

The system comes to equilibrium at 425 °C, and

  • PHI = 0.794 atm
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  • PI2 = 0.0685 atm

Replacing:

Kp=\frac{0.0685*0.0685}{0.794^{2} }

Kp=7.44*10⁻³

<u><em>The value of Kp at this temperature is 7.44*10⁻³</em></u>

4 0
3 years ago
Write a balanced overall reaction from these unbalanced half-reactions sn and ag
loris [4]
Balance each one by adding electrons to make the charges on both sides the same:

Sn--> Sn2+ + 2 e-
Ag+ + 1 e- --> Ag

Now, you have to have the same number of electrons in the two half-reactions, so multiply the second one by 2 to get:

2 Ag+ + 2 e- --> 2 Ag

Now, just add the two half reactions together, cancelling anything that's the same on both sides:

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Aloiza [94]
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3 years ago
How many molecules of aspartame are present in 1.00 mg of aspartame?
kobusy [5.1K]

Answer:

0.2 x 10^19

Explanation:

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3 years ago
Among K, Ca and Ba, which element possess low ionization energy?
deff fn [24]

Among the elements Barium has the lowest Ionization Energy.

<h3>What is Ionization Process ?</h3>

The process by which any neutral atom gets converted into electrically charged by gaining or losing electron is called Ionization Process.

K  is an alkali metal  it has to lose one electron to attain stable electronic configuration of an inert gas

For removing second electron , a stable configuration has to be broken and so will require high amount of energy.

Ca and Ba are alkaline earth metals.

They both have to lose 2 electrons to attain  stable electronic configuration of noble gas.

They have low Iow Ionization Energy as compared to K.

Ca has higher  Ionization Energy as compared to Ba because when we move down the periodic table , The ionization energy decreases.

Hence , Among the elements Barium has the lowest Ionization Energy.

To know more about Ionization Process

brainly.com/question/6638422

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2 years ago
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