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As I am reading the problem, I see they gave you two pressures, one volume and they are asking for another volume. this should give you a hint that you need to use the following formula.
P1V1= P2V2
P1= 1.00 atm
V1= 0.50 ft³
P2= 3.00 atm
V2= ?
Now we plug the values
(1.00 x 0.50)= (3.00 x V2)
V2= 0.17 ft³
Answer:
156 g
Explanation:
Let's consider the following reaction.
2 NaN₃(s) → 2 Na(s) + 3 N₂
(g)
We can find the moles of N₂ using the ideal gas equation.
P × V = n × R × T
1.50 atm × 60.0 L = n × (0.08206 atm.L/mol.K) × 305 K
n = 3.60 mol
The molar ratio of N₂ to NaN₃ is 3:2. The moles of NaN₃ are:
3.60 mol N₂ × (2 mol NaN₃ / 3 mol N₂) = 2.40 mol NaN₃
The molar mass of NaN₃ is 65.01 g/mol. The mass of NaN₃ is:
2.40 mol × 65.01 g/mol = 156 g
Answer:
Electrons on atoms have different amounts of energy proportional to the distance of their orbital from the nucleus. So in the flame, electrons get excited and pushed to higher energy levels by the heat energy. When they fall back down, they give off photons of light of different colors, based upon how far they fall.
Answer:
Kinetic energies of all the gases are same.
Explanation:
The average kinetic energy of molecules of a gas is given by the formula:
K.E = (3/2)KT
where,
K.E = Average Kinetic Energy of the molecule
K = Boltzman's Constant = 1.38 x 10^-23 J/K
T = Absolute temperature of gas
Since, all the gases are in a mixture, and the temperature of the gases must be same and equal to the temperature of mixture.
Therefore, all the terms in the formula are constant and the <u>Average Kinetic Eenergies of all the gases in the mixture (namely, Neon Ne, Krypton Kr, Radon Rn), equal.</u>
