Answer:
183.3 Km.
Explanation:
- The jet airplane reaches 846 Km in an hour (60.0 min).
- The question is what the distance the airplane covers in 13.0 min.
<em>Using cross multiplication:</em>
846 Km → 60.0 min
??? Km → 13.0 min
∴ The distance that the airplane covers in 13.0 min = (846 Km) (13.0 min) / (60.0 min) = 183.3 Km.
First, we require the combustion equation of propane:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
We see that each mole of propane produces 4 moles of water.
Now, we calculate the moles of water required: 75 / 18.02
Moles required = 4.16
Moles of propane required for this are: 4.16 / 4 = 1.04 moles
Each mole of gas occupies 22.14 liters, so the volume of propane required are 1.04 * 22.14 = 23.03 L
23 L of propane are required
