All categories

3 years ago

Lance wrote the number 4,953. Then he wrote a number with a 9 digit that is 100 times the value of the 9 in 4,953.

Mathematics

2 answers:

taurus [48]3 years ago

5 0

Answer:

The Number written by lance = 4,953

Face value of ,9 in 4953 = 9

Place value of , 9 in 4953 = 9 × 100=900

So, the number could be

1. 100 × Face value of , 9 in 4,953 = 100 × 9=900

2. 100 × Place value of , 9 in 4,953 =100 × 900=90,000

Andrei [34K]3 years ago

4 0

the answer is 4953 * 100 which is equal to 495300

You might be interested in

Explain how you can round 25.691 to the greatest place.

labwork [276]

If it is to the tenth, then you have to look at the hundredth place, if the number in the hundredth place is over 5 or 5, then you have to make the number in the tenth place move up one digit if it isn't over 5 or 5, then you don't do anything

4 0

2 years ago

Read 2 more answers

Natalia is calculating the areas of parallelograms using the following formula: Area=bh, where b represents the base of the para

lions [1.4K]

4 inches think you believe in yourself

3 0

2 years ago

A________ has cross-sectional shapes, taken parallel to a base, that are similar

alexdok [17]

Answer:

I think it is C

Step-by-step explanation

<em>cube has equal sides and is parallel.</em>

3 0

2 years ago

Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe

valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

$(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3$

(a)

$(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\$

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

$(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

$(x+1)(x-1)=x^{2}-1^{2}\\$

we can say that this is neither sum nor difference of cube as it's difference of squares.

(d)

$(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)$

by comparison with formula this is equal to

$x^{3}+4^{3}\\$

Hence this is sum of cubes

(e)

$(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

To know more about cubes visit: brainly.com/question/107100

8 0

1 year ago

the store owner gave a 35% discount yeah Joe and Carol so had to pay $247 for the camera what was the original price of the came

frozen [14]

From the given statement, we know the following...

0.35x = $247 where x = the orginial number

So if we solve for x by dividing by 0.35

x = $247/0.35 = $705.71

7 0

2 years ago