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Roman55 [17]
2 years ago
13

The specification for a length x is 43.6 cm with a tolerance of 0.1 cm. Write the specification as an absolute value inequality.

Mathematics
2 answers:
Burka [1]2 years ago
8 0

Answer:

43.5\leq x\leq 43.7

Step-by-step explanation:

We have been given that the specification for a length x is 43.6 cm with a tolerance of 0.1 cm. We are asked to write given specification as an absolute value.

|\text{Actual-Ideal}|\leq \text{Tolerence}

Upon substituting our given values, we will get:

|x-43.6|\leq 0.1

Using absolute value definition |x|\leq a=-a\leq x\leq a, we will get:

-0.1\leq x-43.6\leq 0.1

-0.1+43.6\leq x-43.6+43.6 \leq 0.1+43.6

43.5\leq x \leq 43.7

Therefore, our required inequality would be 43.5\leq x \leq 43.7.

SSSSS [86.1K]2 years ago
3 0
My answer to the problem is as follows:

Expressed as an absolute value. 
<span>
The difference between the actual length, x, and the specification, 43.6, can be no more than 0.1 </span>
<span>
|x - 43.6| ≤ 0.1 <––––– 
</span>
<span>The 43.6 is the target length, and the tolerance of 0.1 is how far off from the target is acceptable.</span>
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