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Dovator [93]
1 year ago
6

What is the difference between dissolving and dissociating and how does this relate to the van't hoff factor?

Chemistry
1 answer:
Nastasia [14]1 year ago
6 0

Solvation is the process of dissolving.

Dissociation is the separation of a substance into charged components during dissolution.

<h3>What is the difference between dissolving and dissociating?</h3>

Dissolution (dissolving), which simply refers to becoming solvated by the solvent, is a subset of dissociation, which is particularly the separation of two charged ions in solution. When the solvent completely envelops each individual solute molecule, solvation takes place. By definition, something that is dissociated in a solvent must be dissolved in it. For instance, the salt dissociates in water, which is how it dissolves in water. In water, ethanol dissolves but does not dissociate; it remains ethanol.

<h3>How does Van't Hoff's factor work?</h3>

The Van't Hoff factor is a tool used to compare the real number of moles of solute injected to create a solution to the apparent amount produced by colloidal characteristics.

<h3>What is the Van't Hoff factor's value?</h3>

Van't Hoff factor's value is:-

  • No association or dissociation                  i=1
  • Dissociation                                             i<1
  • Association                                               i>1

Learn more about Van't Hoff's factor here:-

brainly.com/question/24598605

#SPJ4

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8 0
2 years ago
What is the SI unit used to measure weight?
stepladder [879]

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7 0
2 years ago
Ethanol (CH3CH2OH), the intoxicant in alcoholic beverages, is also used to make other organic compounds. In concentrated sulfuri
Fed [463]

Answer:

a) 88.48%

b) 0.05625 mol

Explanation:

2CH₃CH₂OH(l) → CH₃CH₂OCH₂CH₃(l) + H₂O(g)         Reaction 1

CH₃CH₂OH(l) → CH₂═CH₂(g) + H₂O(g)                        Reaction 2

a) CH₃CH₂OH = 46.0684 g/mol

   CH₃CH₂OCH₂CH₃ = 74.12 g/mol

1 mol CH₃CH₂OH ______  46.0684 g

x                            ______   50.0 g

x = 1.085 mol  CH₃CH₂OH

1 mol  CH₃CH₂OCH₂CH₃ ______  74.12 g g

y                           ______   35.9 g

y = 0.48 mol   CH₃CH₂OCH₂CH₃

100% yield _____ 0.5425 mol CH₃CH₂OCH₂CH₃

w                _____  0.48 mol CH₃CH₂OCH₂CH₃

w = 88.48%

b) Only 0.96 mol of ethanol reacted to form diethyl ether. This means that 0.125 mol of ethanol did not react. 45% of 0.125 mol reacted to form ethylene. Therefore, 0.05625 mol of ethanol reacted by the side reaction (reaction 2). Since 1 mol of ethanol leads to 1 mol of ethylene, 0.05625 mol of ethanol produces 0.05625 mol of ethylene.

4 0
3 years ago
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