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notka56 [123]
3 years ago
8

How many moles of N are in 0.223 g of N2O

Chemistry
1 answer:
liq [111]3 years ago
4 0
Answer:
There are twice the molar quantity of nitrogen atoms in nitrous oxide, i.e.
1×10−2⋅mol
Moles of nitrous oxide

=

0.217
⋅
g
44.013
⋅
g
⋅
m
o
l
−
1

=

5
×
10
−
3
⋅
m
o
l
.
Given the composition of
N
2
O
, there are this
2
×
5
×
10
−
3
⋅
m
o
l
of nitrogen atoms.
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Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?
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Answer: Option (B) is the correct answer.

Explanation:

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And in between reactants and products a forward arrow is placed pointing towards the products.

Therefore, the reaction for carbon burns in the presence of oxygen to give carbon dioxide will be written as follows.

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A sample of gas with a mass of 21.3 g is confined to a vessel of volume 7.73 L at 0.880 atm and 30.00C.
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(a) 77.9 g/mol

(b) 3.18 g / L

Explanation:

<u>(a)</u> We need to use the ideal gas law, which states: PV = nRT, where P is the pressure, V is the volume, n is the moles, R is the gas constant, and T is the temperature in Kelvins.

Notice that we don't have moles; we instead have the mass. Remember, though that moles can be written as m/M, where m is the mass and M is the molar mass. So, we can replace n in the equation with m/M, or 21.3/M. The components we now have are:

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- n: m/M = 21.3 g / M

- R: 0.08206

- T: 30.00°C + 273 = 303 K

Plug these in:

PV = nRT

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