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MariettaO [177]
3 years ago
8

How many moles of oxygen are in 52.5 grams of oxygen gas?

Chemistry
1 answer:
adell [148]3 years ago
3 0
An oxygen gas is a diatomic molecule which means that each molecule is composed of 2 atoms. Its symbol is O2. 

Each oxygen atom has a molar mass of 16 g/mol. The molar mass of oxygen gas is calculated below,
                         molar mass = 2 x (16 g/mol) = 32 g/mol

To determine the number of moles in 52.5 grams of oxygen, divide the given mass by the calculated molar mass.
 
                                 n = 52.5 grams / (32 gram/ mol)
                                     n = 1.64 moles

Thus, there are 1.64 moles of oxygen gas. 
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My favorite student weighs in at 125 pounds. How many<br>kilograms do they weigh?​
fiasKO [112]

Answer:

56.69905

Explanation:

The conversion factor from pounds to kilograms is 0.45359237, which means that 1 pound is equal to 0.45359237 kilograms.

7 0
3 years ago
Which state of matter undergoes changes in volume most easily
dusya [7]
The matter of changes in volume is gas
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What would you need to do to calculate the molarity of 10g of NaCl in 2kg of water?
Artist 52 [7]

Answer:

B) we will convert the 10 g of NaCl into moles.

Explanation:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

we will convert the 10 g of NaCl into moles.

Number of moles of NaCl:

Number of moles = mass/molar mass

Number of moles = 10 g/ 58.44 gmol

Number of moles = 0.17 mol

1 Kg = 1 L

Molarity = 0.17 mol / 2 L

Molarity = 0.085 mol/L

Molarity = 0.085 M

6 0
3 years ago
Read 2 more answers
The half life of a new isotope found on Mars is 2 years. It takes 10 years to get the sample back to Earth. If the astronauts st
yawa3891 [41]

Answer:

3.99 g

Explanation:

The following data were obtained from the question:

Half life (t½) = 2 years.

Original amount (N₀) = 128 g

Time (t) = 10 years

Amount remaining (N) =..?

Next, we shall determine the rate of disintegration of the isotope. This can be obtained as follow:

Half life (t½) = 2 years.

Decay constant (K) =.?

K= 0.693/t½

K = 0.693/2

K = 0.3465 year¯¹.

Finally, we shall determine the amount remaining after 10 years i.e the amount remaining when they arrive on Earth. This can be obtained as follow:

Original amount (N₀) = 128 g

Time (t) = 10 years

Decay constant (K) = 0.3465 year¯¹.

Amount remaining (N) =..?

Log (N₀/N) = kt/2.3

Log (128/N) = (0.3465 × 10)/2.3

Log (128/N) = 1.5065

Take the antilog of 1.5065

128/N = Antilog (1.5065)

128/N = 32.1

Cross multiply

128 = 32.1 × N

Divide both side by 32.1

N = 128/32.1

N = 3.99 g

Therefore, the amount remaining is 3.99 g

3 0
4 years ago
The freezing point of pure benzene (C₆H₆) is 5. 49 °C. The freezing point of a solution made using toluene (C₇H₈) in benzene is
Irina18 [472]

The molality of the toluene is 1.46 mol/kg.

<h3>What is molality?</h3>

The molality of a solution is its molal concentration. Molal concentration is denoted by m. It is the mol of solute dissolves in 1 Kg solvent.

The depression at freezing point is directly proportional to the molality of the solution. The equation we use for this type of problem is:

ΔT=iKm f_m

Where,  ΔT f_m is depression at freezing point, i is Van't hoff factor, m is molality and K_f is the freezing point depression constant.

Toluene is a non-electrolyte and so the value of i for this is 1.

Depression at a freezing point is given as -13.0^0 and the K_f is given as 5.12. So, we could calculate the molality of the solution using the equation written above.

Let's plug in the values in the equation:

ΔT=iKmf_m

-7.51 =1 x5. 12 xm

m = \frac{7.51}{5. 12}

m = 1.46 m

It means the molality of the solution is 1.46 mol/kg.

Hence, the molality of the solution is 1.46 mol/kg.

Learn more about the molality of the solution here:

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3 0
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