Answer:
260 kPa
Explanation:
To answer this problem we can use <em>Gay-Lussac's law</em>, which states that at a constant volume (such as is the case with a rigid container):
Where in this case:
- T₂ = 273 °C ⇒ 273 + 273.16 = 546 K
We <u>input the data</u>:
- 340 kPa * 546 K = P₂ * 713 K
And <u>solve for P₂</u>:
Acids have ph less than 7 and alkali have ph more than 7
Answer:
<h2>The answer is 2500 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration is given by
<h3>Force = mass × acceleration</h3>
From the question
mass of car = 25 kg
acceleration = 100 m/s²
The force is
Force = 25 × 100
We have the final answer as
<h3>2500 N</h3>
Hope this helps you
Answer:
The pressure of the gas at 23 C is 179.92 kPa.
Explanation:
Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.
In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.
Gay-Lussac's law can be expressed mathematically as follows:

Studying two states, one initial 1 and the other final 2, it is satisfied:

In this case:
- P1= 310 kPa
- T1= 237 C= 510 K (being 0 C= 273 K)
- P2= ?
- T2= 23 C= 296 K
Replacing:

Solving:

P2= 179.92 kPa
<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>