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Andrei [34K]
3 years ago
11

You can increase the surface area of a block of ice by

Chemistry
1 answer:
lozanna [386]3 years ago
3 0
Surface area<span> of a solid object is a measure of the total </span>area<span> that is occupied by the surface of object. 

If two objects has same mass, then smaller size particles will have greater surface area. 

Thus, in order to increase the surface area of ice, one can crush it into small particles. Due to crushing, particles will break into smaller size and eventually this will result in larger surface area.  </span>
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The elements beyond uranium on the periodic table of the elements are called the ------- elements
iris [78.8K]
The answer is elements
4 0
3 years ago
A rigid container of O 2 has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273°C ?
Vinvika [58]

Answer:

260 kPa

Explanation:

To answer this problem we can use <em>Gay-Lussac's law</em>, which states that at a constant volume (such as is the case with a rigid container):

  • P₁T₂=P₂T₁

Where in this case:

  • P₁ = 340 kPa
  • T₂ = 273 °C ⇒ 273 + 273.16 = 546 K
  • P₂ = ?
  • T₁ = 713 K

We <u>input the data</u>:

  • 340 kPa * 546 K = P₂ * 713 K

And <u>solve for P₂</u>:

  • P₂ =  260 kPa
5 0
3 years ago
Which number represents an acidic pH, 4 or 9?
katrin2010 [14]
Acids have ph less than 7 and alkali have ph more than 7

7 0
3 years ago
Read 2 more answers
If a 25 kg car accelerates at a speed of 100 m/s², what will the force of the car be?
igomit [66]

Answer:

<h2>The answer is 2500 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration is given by

<h3>Force = mass × acceleration</h3>

From the question

mass of car = 25 kg

acceleration = 100 m/s²

The force is

Force = 25 × 100

We have the final answer as

<h3>2500 N</h3>

Hope this helps you

5 0
4 years ago
5. A gas has a pressure of 310 kPa at 237 degrees C.<br>What will its pressure be at 23 degrees C?)​
slavikrds [6]

Answer:

The pressure of the gas at 23 C is 179.92 kPa.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Studying two states, one initial 1 and the other final 2, it is satisfied:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 310 kPa
  • T1= 237 C= 510 K (being 0 C= 273 K)
  • P2= ?
  • T2= 23 C= 296 K

Replacing:

\frac{310 kPa}{510 K} =\frac{P2}{296 K}

Solving:

P2=296 K*\frac{310 kPa}{510 K}

P2= 179.92 kPa

<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>

5 0
3 years ago
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