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Montano1993 [528]
3 years ago
10

Calculate the PH of a solution 0.030 MH2SO4

Chemistry
1 answer:
Zinaida [17]3 years ago
4 0

Answer:

pH= 2- log3

Explanation:

H2SO4 + H2O -> HSO4^(-) + H30^(+)

0.03M ___ ___

___ 0.03M 0.03M

H30^(+) : C = 0.03M

pH= - log( [H3O^(+)] ) => pH= - log {3× 10^(-2)} => pH = 2 - log3

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Se quema una muestra de 1.00 g de octano (C8H18) en un calorímetro de bomba que contiene 1200.0 cm3de agua a una temperatura ini
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Pls Help this is my last question on the quiz - Which two types of energies involve changes in atoms or atom rearrangement?
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2 years ago
Which of the following could be the rate equation for a first order reaction? please help this is timed
wel

Rate = k[A] = first order reaction

<h3>Further explanation</h3>

Given

Rate law

Required

A first-order reaction

Solution

The rate law : equation for the rate of chemical reaction

For reaction

aA + bB ⇒ C

The rate : r = k[A]ᵃ[B]ᵇ

The sum of exponents(a+b) is the reaction order

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a. a+b = 2, second order reaction

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7 0
3 years ago
Consider the following reaction: C2H4(g) + H2O(g) ⇌ C2H5OH(g) ΔHo = -45.8 kJ/mol At 298K the equilibrium constant, KP, for this
Ber [7]

Answer:

ΔG = 2721.891 J/mol

Explanation:

  • C2H4(g) + H2O(g) ↔ C2H5OH(g)

∴ ΔH°rxn = - 45.8 KJ/mol

∴ Kp = 28.5

If p(C2H4) = p(H2O) = p(C2H5OH) = 3.0 atm ⇒ ΔG°rxn = ?

⇒ Kp = (PC2H5OH/P*) / (PC2H4/P*)(PH2O/P*)

∴ P* = 1 atm

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  • Kp = e∧( - ΔG/RT)

⇒ Ln Kp = - ΔG/RT

⇒ ΔG = - RT LnKp

∴ T = 298 K

∴ R  = 8.314 J/mol.K

⇒ ΔG = - ((8.314 J/mol.K)(298 K)) Ln(0.33)

⇒ ΔG = 2721.891 J/mol

3 0
3 years ago
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