Question

Suppose that the pressure of 0.66 L of gas is 424.9 mm Hg when the temperature is 261.2 K. At what temperature is the volume 7.63 L and the pressure 872.15 mm Hg?
Select one:
a. 6200
b. 1.24e4
c. 3010
d. 11.0

Answer 1

Answer:

• Option a. 6200 K

Explanation:

1) Data:

• V₁ = 0.66 liter
• P₁ = 42.9 mmHg
• T = 261.2 K

• T₂ = ?
• V₂ = 7.63 liter
• P₂ = 872.15 mmHg

2) Formula:

Combined law of gases:

• P₁ V₁ / T₁ = P₂ V₂ / T₂

3) Solution:

• Solve for T₂:

T₂ = P₂ V₂ T₁ / (P₁ V₁)

• Substitute:

T₂ = 872.15 mmHg × 7.63 liter × 261.2 K / ( 424.9 mmHg × 0.66 liter)

T₂ = 6198 K

• Rounding to 2 significant figures, that is 6200 K, which is the first choice.

Answer 2

I believe it’s a. 6200