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Brilliant_brown [7]
3 years ago
10

Sterling silver contains 92.5% silver and 7.5% copper. A sterling silver dish weighs 185.0 g. What mass of copper is in the dish

?
Chemistry
2 answers:
lord [1]3 years ago
6 0

Answer:

I believe the answer is 14g

elena-14-01-66 [18.8K]3 years ago
5 0

<u>Answer:</u> The mass of copper in the dish is 13.875 grams.

<u>Explanation:</u>

We are given:

(m/m) % of copper = 7.5 %

This means that 7.5 grams of copper are present in 100 grams of solution.

We need to find the mass of copper in 185 grams of sterling silver dish.

To calculate the mass of copper, we use unitary method, we get:

In 100 g of sterling silver dish, the mass of copper is 7.5 grams.

So, in 185 grams of sterling silver dish, the mass of copper is = \frac{7.5g}{100g}\times 185g=13.875g

Hence, the mass of copper in the dish is 13.875 grams.

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Answer:
I. Changing the pressure:
Increasing the pressure: the amount of H₂S(g) will increase.
Decreasing the pressure: the amount of H₂S(g) will decrease.
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Decreasing the temperature: the amount of H₂S(g) will increase.
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Decreasing the H₂ concentration: the amount of H₂S(g) will decrease.
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Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
I. Changing the pressure:
When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
For the reaction: CH₄(g) + 2H₂S(g) ⇄ CS₂(g) + 4H₂(g),
The reactants side (left) has 3.0 moles of gases and the products side (right) has 5.0 moles of gases.
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H₂ is a part of the products, increasing H₂ increases the amount of the products. So, the reaction will be shifted to the left to suppress the effect of increasing H₂ and the amount of H₂S(g) will increase.
Decreasing the H₂ concentration:
H₂ is a part of the products, decreasing H₂ decreases the amount of the products. So, the reaction will be shifted to the right to suppress the effect of decreasing H₂ and the amount of H₂S(g) will decrease.
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