1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bulgar [2K]
3 years ago
11

A volume of cool air rapidly descends from the top of a mountain. the air is a poor thermal conductor, but its temperature incre

ases as its volume decreases, because of the increase in atmospheric pressure as it reaches the ground. what thermodynamic process takes place
Physics
1 answer:
AleksandrR [38]3 years ago
5 0
These are all the characteristics of what is called the adiabatic process. This process occurs when there is no transfer of heat between the surroundings and the thermodynamic system. This is a key process for thermodynamics and it is of great importance for the first law of thermodynamics. 
You might be interested in
State coulomb's law mathematically
Vsevolod [243]

Coulomb's law is express as:

\begin{gathered} F=k\frac{q_1q_2}{r^2} \\ \text{ where} \\ k\text{ is Coulomb's constant} \\ q_1\text{ and }q_2\text{ are the charges} \\ r\text{ is the distance between charges} \end{gathered}

7 0
1 year ago
Assume that block A which has a mass of 30 kg is being pushed to the left with a force of 75 N along a frictionless surface. Wha
Veronika [31]

Answer:

The force of friction acting on block B is approximately 26.7N.  Note: this result does not match any value from your multiple choice list. Please see comment at the end of this answer.  

Explanation:

The acting force F=75N pushes block A into acceleration to the left. Through a kinetic friction force, block B also accelerates to the left, however, the maximum of the friction force (which is unknown) makes block B accelerate by 0.5 m/s^2 slower than the block A, hence appearing it to accelerate with 0.5 m/s^2 to the right relative to the block A.

To solve this problem, start with setting up the net force equations for both block A and B:

F_{Anet} = m_A\cdot a_A = F - F_{fr}\\F_{Bnet} = m_B\cdot a_B = F_{fr}

where forces acting to the left are positive and those acting to the right are negative. The friction force F_fr in the first equation  is due to A acting on B and in the second equation due to B acting on A. They are opposite in direction but have the same magnitude (Newton's third law). We also know that B accelerates 0.5 slower than A:

a_B = a_A-0.5 \frac{m}{s^2}

Now we can solve the system of 3 equations for a_A, a_B and finally for F_fr:

30kg\cdot a_A = 75N - F_{fr}\\24kg\cdot a_B = F_{fr}\\a_B= a_A-0.5 \frac{m}{s^2}\\\implies \\a_A=\frac{87}{54}\frac{m}{s^2},\,\,\,a_B=\frac{10}{9}\frac{m}{s^2}\\F_{fr} = 24kg \cdot \frac{10}{9}\frac{m}{s^2}=\frac{80}{3}kg\frac{m}{s^2}\approx 26.7N

The force of friction acting on block B is approximately 26.7N.

This answer has been verified by multiple people and is correct for the provided values in your question. I recommend double-checking the text of your question for any typos and letting us know in the comments section.

6 0
3 years ago
Read 2 more answers
A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular
blondinia [14]
The answer is D. Hope this helps you!
6 0
3 years ago
A 900 N student runs up the stairs 3.5 m high in 12<br> seconds. How much POWER do they generate?
never [62]

Answer:

Ur litterly dog water ✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️

4 0
3 years ago
Find the magnitude of the electric field due to a charged ring of radius "a" and total charge "Q", at a point on the ring axis a
34kurt

Answer:

E=\frac{KQ}{2\sqrt 2a^2}

Explanation:

We are given that

Charge on ring= Q

Radius of ring=a

We have to find the magnitude of electric filed on the axis at distance a from the ring's center.

We know that the electric field at distance x from the center of ring of radius R is given by

E=\frac{kQx}{(R^2+x^2)^{\frac{3}{2}}}

Substitute x=a and R=a

Then, we get

E=\frac{KQa}{(a^2+a^2)^{\frac{3}{2}}}

E=\frac{KQa}{(2a^2)^{\frac{3}{2}}}

E=\frac{KQa}{2\sqrt 2a^3}

E=\frac{KQ}{2\sqrt 2a^2}

Where K=9\times 10^9 Nm^2/C^2

Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center=\frac{KQ}{2\sqrt 2a^2}

4 0
3 years ago
Other questions:
  • I NEED HELPP!!!!!!!!!!!!!!
    12·1 answer
  • Car crosses the first third of the road with unknown speed and the rest of the road with the speed of 50 km/h. What is the the s
    9·1 answer
  • The case whereby sound waves are heard at either a higher or lower pitch due to an object's motion is called:
    14·2 answers
  • What happens when a gas changes state to become a liquid
    14·1 answer
  • Pump A can fill a tank of water in 5 hours. Pump B can fill the same tank in 8 hours. How long does it take the two pumps workin
    15·2 answers
  • suppose 384g of steam originally at 100C is quickly cooled to produce liquid water at 31C. How much heat must be removed from th
    13·1 answer
  • You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
    15·1 answer
  • Air pollution is a negative effect of using this renewable resource to generate power.
    7·2 answers
  • Convert 365 years to days. Using one step conversion. :) Please help w this
    6·2 answers
  • 3 a A motorcyclist starts from rest and reaches
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!