Appeal system enables the higher court to review the case once again. Possible situation for appeal arises when the defendant consider punishment very tough.
<u>Explanation:</u>
The Appeal system is very important in the legal system. Appeal means a process which helps in reviewing the cases. In case of the appeal, a request is made to a higher court to look into the case once again.
This process helps those who feel that the earlier judgment in case of the case was not correct.
The Possible situation where someone needs to appeal is when the defendant is found guilty and we feel that the punishment given is very harsh. This is possible mostly in criminal cases.
The amount of heat energy required to raise the temperature of a unit mass of a material to one degree is called D. its heat capacity.
The relationship of the heat when applied to the object and the change in temperature of the object when heat is being applied is directly proportional to each other. This means that when heat is applied to the object, the temperature of the object increases and when heat is not applied to the object, the temperature of the object decreases.
I found this using the app Socratic. When I took physics in high school it helped me so much.
Answer:
![\Delta V = 1.8 \times 10^7 V](https://tex.z-dn.net/?f=%5CDelta%20V%20%20%20%20%3D%201.8%20%5Ctimes%2010%5E7%20V)
Explanation:
GIVEN
diameter = 15 fm =
m
we use here energy conservation
![K_{i}+U_{i} =K_{f}+U_{f}](https://tex.z-dn.net/?f=K_%7Bi%7D%2BU_%7Bi%7D%20%3DK_%7Bf%7D%2BU_%7Bf%7D)
there will be some initial kinetic energy but after collision kinetic energy will zero
![K_{i} + 0 = 0 + \frac{1}{4 \pi \epsilon _{0}} \frac{(2e)(92e)}{7.5 \times 10^{-15}}](https://tex.z-dn.net/?f=K_%7Bi%7D%20%2B%200%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B4%20%5Cpi%20%5Cepsilon%20_%7B0%7D%7D%20%5Cfrac%7B%282e%29%2892e%29%7D%7B7.5%20%5Ctimes%2010%5E%7B-15%7D%7D)
on solving these equations we get kinetic energy initial
J ..............(i)
That is, the alpha particle must be fired with 35.33 MeV of kinetic energy. An alpha particle with charge q = 2 e
and gains kinetic energy K =e∆V ..........(ii)
by accelerating through a potential difference ∆V
Thus the alpha particle will
just reach the
nucleus after being accelerated through a potential difference ∆V
equating (i) and second equation we get
e∆V = 35.33 Me V
![\Delta V = \frac{35.33}{2} MV\\\Delta V = 1.8 \times 10^7 V](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20%5Cfrac%7B35.33%7D%7B2%7D%20%20MV%5C%5C%5CDelta%20V%20%20%20%20%3D%201.8%20%5Ctimes%2010%5E7%20V)
Answer:
Specific heat at constant pressure is = 1.005 kJ/kg.K
Specific heat at constant volume is = 0.718 kJ/kg.K
Explanation:
given data
temperature T1 = 50°C
temperature T2 = 80°C
solution
we know energy require to heat the air is express as
for constant pressure and volume
Q = m × c × ΔT ........................1
here m is mass of the gas and c is specific heat of the gas and Δ
T is change in temperature of the gas
here both Mass and temperature difference is equal and energy required is dependent on specific heat of air.
and here at constant pressure Specific heat is greater than the specific heat at constant volume,
so the amount of heat required to raise the temperature of one unit mass by one degree at constant pressure is
Specific heat at constant pressure is = 1.005 kJ/kg.K
and
Specific heat at constant volume is = 0.718 kJ/kg.K