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saveliy_v [14]
3 years ago
6

A small piece of dust of mass m = 4.1 µg travels through an electric air cleaner in which the electric field is 466 N/C. The ele

ctric force on the dust particle is equal to the weight of the particle.
(a) What is the charge on the dust particle?
C

(b) If this charge is provided by an excess of electrons, how many electrons does that correspond to?
electrons
Physics
1 answer:
pantera1 [17]3 years ago
7 0

Answer:

Explanation:

mass, m = 4.1 x 10^-6 g

Electric field, E = 466 N/C

Electric force = weight

(a) Electric force = q x E = m x g

where, q be the charge on the dust particle.

q x 466 = 4.1 x 10^-6 x 9.8

q = 8.62 x 10^-8 C

(b) Number of electron  = charge / charge of one electron

n = 8.62 x 10^-8 / (1.6 x 10^-19)

n = 5.4 x 10^11

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Find the coordinates of the center of mass of the triangle.

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- So let’s say we have a triangle with vertices at points (0,0) , (a,0) , and (0,b).

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  • Median from (a,0) to midpoint (0,b/2) of opposite side has equation:

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                                     bx = b/3

                                     x = a / 3

  • So the distance from the median to each leg of the triangle is 1/3 length of other leg.

- So the coordinates of the centroid for right angle triangle would be:

                                   [ 2a/3 , b/3 ]

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