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2 years ago

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What's the pressure on solids

1 answer:

Studentka2010 [4]2 years ago

5 0

<span>As in all the solids, their atoms are arrange in certain intermolecular distances. When the pressure in the solid, it changes this intermolecular distances which causes selectively changes all those effects which are associated with the interactions between molecules. Pressure changes the phonon frequencies, changes in phonon line shape in the solid. This is also responsible for change in melting and boiling points. The pressure may also cause for phase transition in many solids.</span>

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Air in a thundercloud expands as it rises. If its initial temperature is 292 K and no energy is lost by thermal conduction on ex

tiny-mole [99]

Answer:

Explanation:

It is a case of adiabatic expansion .

$T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}$

T₁ , T₂ are initial and final temperature , V₁ and V₂ are initial and final volume.

Given ,

V₂ = 3 V₁ and T₁ = 292 . γ for air is 1.4 .

$( 3 )^{\gamma-1}= \frac{292}{ T_2}$

$( 3 )^{1.4-1}= \frac{292}{ T_2}$

1.552 = 292 / T₂

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a spring is used to launch a ball vertically into the air. the spring has a spring constant of 200N/m and is compressed by 5 cm.

zhannawk [14.2K]

Answer:

2.55 m

Explanation:

Elastic energy = gravitational energy

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2 years ago

The wires in a household lamp cord are typically 3.5 mm apart center to center and carry equal currents in opposite directions.

zhuklara [117]

Explanation:

It is given that,

Distance between wires, d = 3.5 mm = 0.0035 m

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$\dfrac{F}{l}=\dfrac{\mu_o I^2}{2\pi r}$

Power, P = V × I

$I=\dfrac{P}{V}=\dfrac{100}{120}=0.83\ A$

This gives, $\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times (0.83)^2}{2\pi \times 0.0035}$

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(b) Since, the two wires carry equal currents in opposite directions. So, teh force is repulsive.

(c) This force is negligible.

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2 years ago

The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?

BigorU [14]

1. Frequency: $7.06\cdot 10^{14} Hz$

The frequency of a light wave is given by:

$f=\frac{c}{\lambda}$

where

$c=3\cdot 10^{-8} m/s$ is the speed of light

$\lambda$ is the wavelength of the wave

In this problem, we have light with wavelength

$\lambda=425 nm=425\cdot 10^{-9} m$

Substituting into the equation, we find the frequency:

$f=\frac{c}{\lambda}=\frac{3\cdot 10^{-8} m/s}{425\cdot 10^{-9} m}=7.06\cdot 10^{14} Hz$

2. Period: $1.42 \cdot 10^{-15}s$

The period of a wave is equal to the reciprocal of the frequency:

$T=\frac{1}{f}$

The frequency of this light wave is $7.06\cdot 10^{14} Hz$ (found in the previous exercise), so the period is:

$T=\frac{1}{f}=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s$

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2 years ago

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