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irina [24]
3 years ago
15

What are the formulas to calculate acceleration A. velocity and time B. displacement and time C. Change in distance and time D.

Change in velocity and time
Physics
1 answer:
Gnoma [55]3 years ago
3 0
I believe the answer to this is D
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The distance between the lenses in a compound microscope is 18 cm. The focal length of the objective is 1.5 cm. If the microscop
Blababa [14]

Answer:

The focal length of eye piece is 6.52 cm.

Explanation:

Given that,

Angular Magnification of the microscope M = -46

the distance between the lens in microscope L= 16 cm

The focal length of objective f₀ = 1.5 cm

Normal near point N = 25 cm

Have to find focal length of eye piece f ₙ =?

The angular magnification is given by

M ≈ - (L-fₙ)N/f₀fₙ

Rearranging for fₙ

fₙ =L(1 - Mf₀/N)⁺¹

   =18/2.76

fₙ =  6.52 cm

The focal length of eye piece is 6.52 cm.

6 0
3 years ago
(a) Calculate the tension in a vertical strand of spiderweb if a spider of mass 5.00 ✕ 10-5 kg hangs motionless on it.
sertanlavr [38]

a)The tension in the vertical strand will be 0.00049 N.

b))The tension in the horizontal strand will be 0.001284 N.

c)The ratio of tension in the horizontal strand to the tension in the vertical strand will be  2.62.

<h3>What is tension force?</h3>

The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.

Given data;

Mass of spiderweb = 5.00 ✕ 10⁻⁵ kg

The tension in a horizontal strand of a spiderweb, Tₓ

The tension in a  vertical strand of a spiderweb, Tₐ

The angle at which the strand sags, Θ = 10.0°

R is the ratio of  tension in the horizontal strand to the tension in the vertical strand

a)

From the FBD,

The tension  in the vertical strand is equal to the weight of the spider;

Tₐ = W

Tₐ = mg

Tₐ= 5 x 10⁻⁵ kg x 9.8 m / s²

Tₐ= 0.00049 N.

(b)

The super's total vertical forces are zero since it is not moving the value of the tension in the horizontal strand;

Tₓ = mg/( 2sinΘ)

Tₓ = 5 x 10⁻⁵ kg x 9.8 m /s² / ( 2 sin 11° )

Tₓ= 0.001284 N.

c)

R is the tension in the vertical strand divided by the tension in the horizontal strand.

R= Tₐ / Tₓ

R= 0.001284 N / 0.00049 N

R= 2.62

Hence, the tension in a vertical strand of a spiderweb, the tension in a horizontal strand of a spiderweb, and the ratio of tension in the horizontal strand to the tension in the vertical strand will be 0.00049 N, 0.001284 N, and 2.62 respectively.

To learn more about the tension force refer to the link;

brainly.com/question/2287912

#SPJ1

6 0
2 years ago
Astronomers observe two separate solar systems each consisting of a planet orbiting a sun. The two orbits are circular and have
Oxana [17]

Answer:

(D) 3

Explanation:

The angular momentum is given by:

\vec{L}=\vec{r}\ X \ \vec{p}

Thus, the magnitude of the angular momenta of both solar systems are given by:

L_1=Rm_1v_1=Rm_1(\omega R)=R^2m_1(\frac{2\pi}{T_1})=2\pi R^2\frac{m_1}{T_1}\\\\L_2=Rm_2v_2=2\pi R^2\frac{m_2}{T_2}

where we have taken that both systems has the same radius.

By taking into account that T1=3T2, we have

L_1=2\pi R^2\frac{m_1}{3T_2}=\frac{1}{3}2\pi R^2\frac{1}{T_2}m_1=\frac{1}{3}\frac{L_2}{m_2}m_1

but L1=L2=L:

L=\frac{1}{3}L\frac{m_1}{m_2}\\\\\frac{m_1}{m_2}=3

Hence, the answer is (D) 3

HOPE THIS HELPS!!

3 0
2 years ago
The aqueduct passes under Johnson Road in Lancaster through a siphon. The maximum capacity of the aqueduct is 350 m3/s. The heig
Mariulka [41]

Answer:

D ≈ 8.45 m

L ≈ 100.02 m

Explanation:

Given

Q = 350 m³/s (volumetric water flow rate passing through the stretch of channel, maximum capacity of the aqueduct)

y₁ - y₂ = h = 2.00 m (the height difference from the upper to the lower channels)

x = 100.00 m (distance between the upper and the lower channels)

We assume that:

  • the upper and the lower channels are at the same pressure (the atmospheric pressure).
  • the velocity of water in the upper channel is zero (v₁ = 0 m/s).
  • y₁ = 2.00 m  (height of the upper channel)
  • y₂ = 0.00 m  (height of the lower channel)
  • g = 9.81 m/s²
  • ρ = 1000 Kg/m³ (density of water)

We apply Bernoulli's equation as follows between the point 1 (the upper channel) and the point 2 (the lower channel):

P₁ + (ρ*v₁²/2) + ρ*g*y₁ = P₂ + (ρ*v₂²/2) + ρ*g*y₂

Plugging the known values into the equation and simplifying we get

Patm + (1000 Kg/m³*(0 m/s)²/2) + (1000 Kg/m³)*(9.81 m/s²)*(2 m) = Patm + (1000 Kg/m³*v₂²/2) + (1000 Kg/m³)*(9.81 m/s²)*(0 m)

⇒ v₂ = 6.264 m/s

then we apply the formula

Q = v*A  ⇒   A = Q/v ⇒   A = Q/v₂

⇒   A = (350 m³/s)/(6.264 m/s)

⇒   A = 55.873 m²

then, we get the diameter of the pipe as follows

A = π*D²/4   ⇒   D = 2*√(A/π)

⇒   D = 2*√(55.873 m²/π)

⇒   D = 8.434 m ≈ 8.45 m

Now, the length of the pipe can be obtained as follows

L² = x² + h²

⇒ L² = (100.00 m)² + (2.00 m)²

⇒ L ≈ 100.02 m

6 0
2 years ago
Read 2 more answers
Calculate frequency if wavelength is 35 m and wave speed is 546 m/s.
adoni [48]
The answer to your question is a 25.6 HZ
6 0
2 years ago
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