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Lesechka [4]
3 years ago
13

What radiation do remote controls use?

Physics
1 answer:
dalvyx [7]3 years ago
3 0

Answer:

infra red radiation is used

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A 50-loop circular coil has a radius of 3 cm. It is oriented so that the field lines of a magnetic field are perpendicular to th
nikitadnepr [17]

Answer:

-17.8 V

Explanation:

The induced emf in a coil is given as:

E = \frac{-NdB\pi r^2}{dt}

where N = number of loops

dB = change in magnetic field

r = radius of coil

dt = elapsed time

From the question:

N = 50

dB = final magnetic field - initial magnetic field

dB = 0.35 - 0.10 = 0.25 T

r = 3 cm

dt = 2 ms = 0.002 secs

Therefore, the induced emf is:

E = \frac{-50 * 0.25 * \pi * 0.03^2}{0.002} \\E = -17.8 V

Note: The negative sign implies that the EMf acts in an opposite direction to the change in magnetic flux.

6 0
3 years ago
Why is a flower not a good blackbody radiator?
Alecsey [184]

Answer:

A flower emits only visible light

A flower reflects much of the light that hits it

8 0
3 years ago
Why is chemical energy a part of all chemical reactions?
lana [24]
Energy is always needed to preform anything, and chemical energy is one form of energy. Chemical energy is a part of chemical reactions because it involves teh chemicals. 

5 0
3 years ago
Read 2 more answers
Do all substances radiate heat
a_sh-v [17]
I don't believe they do
6 0
3 years ago
Read 2 more answers
If 190 grams of water is cooled from 42.7°C to 21.2° C how much energy was lost by the water?
yanalaym [24]

Answer:

Energy lost by the water is 17.1 x 10³ J .

Explanation:

Specific heat is defined as the amount of energy per unit mass needed to raise the temperature of the substance by a one degree Celsius.

Heat energy gain or loss by any substance is given by :

Q = m x C x ( T₁ - T₂ )     .....(1)

Here m is the mass of the substance, C is specific heat of the substance and T₁ and T₂ are the initial and final temperature of the substance.

According to the problem,

Mass of water, m = 190 gm

Specific heat of water, C = 4.186 J gm⁻¹ ⁰C⁻¹

Initial temperature, T₁ = 42.7⁰ C

Final temperature, T₂ = 21.2⁰ C  

Substitute these values in equation (1).

Heat energy loss by water = 190 x 4.186 x ( 21.2 - 42.7 )

                                            =  -17.1 x 10³ J

In the above value, negative sign denotes the loss in energy.

7 0
4 years ago
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