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VladimirAG [237]
3 years ago
15

En un momento dado , la nadadora de una prueba de natación de 100 m espalda está debajo de la cuerda falsa de salida. Indica a)

El camino recorrido si acaba de salir b) El camino recorrido si ya ha tocado el final de la piscina c) El desplazamiento de la nadadora en los casos a y b ¿Coincide en algún caso con el camino recorrido?
Physics
1 answer:
Virty [35]3 years ago
7 0

Answer:

I only speak English

Explanation:

I'm sorry can you type it in English

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Colonel John P. Stapp, USAF, participated in studying whether a jet pilot could survive emergency ejection. On March 19, 1954, h
borishaifa [10]

we assume the acceleration is constant. we choose the initial and final points 1.40s apart, bracketing the slowing-down process. then we have a straightforward problem about a particle under constant acceleration. the initial velocity is v xi ​ =632mi/h=632mi/h( 1mi 1609m ​ )( 3600s 1h ​ )=282m/s (a) taking v xf ​ =v xi ​ +a x ​ t with v xf ​ =0 a x ​ = t v xf ​ −v xf ​ ​ = 1.40s 0−282m/s ​ =−202m/s 2 this has a magnitude of approximately 20g (b) similarly x f ​ −x i ​ = 2 1 ​ (v xi ​ +v xf ​ )t= 2 1 ​ (282m/s+0)(1.40s)=198m

7 0
3 years ago
Suppose that during a storm the force of the wind blowing against a skyscraper can be expressed by the vector , where each measu
Andrei [34K]

Answer:

Here we do not have the vector, but I will try to give a kinda general solution to this type of problem.

If the vector is written as (a, b, c) we have that the force in the x-axis is of a Newtons, in the y-axis is of b Newtons, and in the z-axis is of c Newtons.

Then, we can calculate the total magnitude of this force as:

F = √( a^2 + b^2 + c^2)

wich gives us the total magnitude of the force, but not a direction or anything like that, this is just a scalar.

3 0
3 years ago
Read 2 more answers
Determine the instantaneous velocity of the car at t = 4.7 s, using time intervals of 0.40 s, 0.20 s, and 0.10 s. (In order to b
weeeeeb [17]

Answer:

4.408 m/s, 4.102 m/s, 4.026 m/s

Explanation:

The question is incomplete. The text of the original question states:

A race car moves such that its position fits the relationship

:

x=(4.0 m/s)t + (0.85 m/s^3) t^3

where x is measured in meters and t in seconds. Determine the instantaneous velocity of the car at t = 4.7 s, using time intervals of 0.40 s, 0.20 s, and 0.10 s.

We can find the instantanoues velocity of the car at any time t by calculating the derivative of the position, so we find:

v(t) = x'(t) = 4.0 m/s + 3\cdot (0.85 m/s^2) t^2 = 4.0 m/s + (2.55 m/s^2) t^2

And now we just need to substitute t=0.40 s, 0.20 s, and 0.10 s to find the corresponding instantaneous velocity:

v(0.40) = 4.0 + 2.55 (0.40)^2 = 4.408 m/s\\v(0.20) = 4.0 + 2.55 (0.20)^2 = 4.102 m/s\\v(0.10) = 4.0 + 2.55 (0.10)^2 = 4.026 m/s

5 0
3 years ago
Does The speed of light in air depends on wavelength and light frequency
Vladimir79 [104]
The answer is
Neither the speed of light in air is going to stay the same no matter what wavelength or frequency

5 0
3 years ago
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A certain planet has an escape speed V. If another planet has twice the radius and twice the mass of the first planet, its escap
Ber [7]

Answer:

option A

Explanation:

Escape velocity of the planet

       v = \sqrt{\dfrac{GM}{R}}

now, it is given that

Second Planet

R₂ = 2R          and M₂ = 2M

now escape velocity of the second planet

now,

       v'= \sqrt{\dfrac{G(2M)}{(2R)}}

on solving

       v'= \sqrt{\dfrac{GM}{R}}

       v'= v

escape velocity of the second planet is equal to first.

The correct answer is option A

4 0
3 years ago
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