Answer: The empirical formula is
Explanation:
Mass of Mg= 46.6 g
Mass of S= 61.4 g
Mass of O = 92.0 g
Step 1 : convert given masses into moles.
Moles of Mg =
Moles of S =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Mg =
For S=
For O =
The ratio of Mg: S: O = 1: 1: 3
Hence the empirical formula is
Answer:
C. The molecules move slower
Explanation:
Answer:
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Number of moles of NO2 = 11.5/(14+16x2) =0.250mol
Mole ratio: 4NO2 to 1O2
Number of moles of O2=0.250/4 =0.0625mol
Mass of O2 produced= 0.0625x32 =2g
Answer: B