Answer:
There is 78.25g NaHCO3 required
Explanation:
Step 1: Balance the equation
2 NaHCO3 → Na2CO3 + CO2 + H20
For 2 moles of NaHCO3 consumed, there is produced 1 mole of Na2CO3, 1 mole of CO2 and 1 mole of H2O.
Step 2: calculating moles of CO2
mass of Co2 = 20.5g
Molar mass of CO2 = 44.01 g/mole
moles of CO2 = 20.5 / 44.01 = 0.4658 moles
Step 3: Calculating moles of NaHCO3
Since we have for 1 mole CO2 produced, there is 2 moles of NaHCO3 consumed.
To calculate number of moles of NaHCO3, we have to multiply the number of moles of CO2, by 2.
⇒ 0.4658 x2 = 0.9316 moles
Step 4: Calculating the mass of NaHCO3
mass of NaHCO3 = moles of NaHCO3 x Molar mass of NaHCO3
mass = 0.9316 moles x 84g/ mole = 78.25g NaHCO3
There is 78.25g NaHCO3 required
Explanation:
There are two aspects of a reaction:
Thermodynamics:
Combustion of the compound is reaction with oxygen.
The carbohydrates contain more content of oxygen as compared to fats.
Hence, carbohydrates have lot of oxygen content which are already partially oxidized as compared to fats. Hence, combustion of the carbohydrates is a faster process.
Kinetics:
The molecular reacts also shows that the combustion of the carbohydrates is a faster process.
Its durability, malleability, etc the basic properties of metals
The activity series goes top to bottom, most active to least active elements, going: Li, K, Ba, Sr, Ca, Na, Mg, Mn, Zn, Fe, Cd, Co, Ni, Sn, Pb, H, Cu, Ag, Hg, Au.
Thus, your list of metals would go from most reactive to least reactive: Li, K, Mg, Zn, Fe, Cu, Au
