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Whitepunk [10]
3 years ago
8

Solution of copper (II) sulfate reacts with solution of sodium hydroxide to ____

Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
4 0

<u>Answer:</u>

A. Solution of copper (II) sulfate reacts with solution of sodium hydroxide to produce "copper hydroxide & solution of sodium sulphate".

B. Solid baking soda (sodium hydrogen carbonate or sodium bicarbonate) reacts with solution of hydrochloric acid to produce "carbon dioxide and water".

<u>Explanation:</u>

When CuSO4 is an acid salt while NaOH is a solid base mixed together. This reaction results into a basic copper hydroxide in the form of pale blue precipitate & sodium sulphate, which is a solution of neutral salt. This process is called as both a double displacement and precipitation reaction.

2NaOH + CuSO4 --> Cu(OH)2 + Na2SO4.

Sodium bicarbonate is used as a cleaner, from a "primitive" material to extract any acidic contaminants, for producing a nobler sample. Sodium bicarbonate and acid mixture generates a salt and carbonic acid that breaks down readily into carbon dioxide and water.

NaHCO3 + HCl → NaCl + H2CO. H2CO3 → H2O + CO2(g).

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3 years ago
Give the nuclear symbol for the isotope of potassium for which a=40?
KATRIN_1 [288]

<span>nuclear symbol consists of three parts: 1. the symbol of the element; 2. the atomic number of the element;3. the mass of the element. for the above problem, the symbol for potassium is k. it's atomic number is 40. the number of protons is 19. so we denote this in the following nuclear symbol; 40 k 19</span>

4 0
3 years ago
Read 2 more answers
A nuclear power plant operates at 40.0% efficiency with a continuous production of 1042 MW of usable power in 1.00 year and cons
Sergio039 [100]

Answer:

3.00 x 10^-11 joules / atom of U-235

Explanation:

We know that the formula for Power = Work done (w)/Time (t)

We need to get the joules from power , since Joules is the SI unit of work.

From the formula P = W/t

W = Power (P) * Time (t)

The SI unit for Time is seconds, hence we change 1 year in seconds

1yr * 365 days/yr * 24hrs/day * 60mins/hr * 60 secs/min = 31536000 secs

It was stated in the question that the plant operates at an efficiency of 40%,

Thus to get the true power we divide the power provided in the question by 0.4 or 40%

= X(0.4) = 1042MW

True Power X = 1042/0.4 = 2605MW

Thus true power = 2605 * 10^6 Watts

Now we have the time in seconds and true power in Watts, we then find the work done.

From our above formula P = W/t

W = P*t = (2605* 10^6) (31536000) =

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5 0
3 years ago
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This is by far probably the best question I've answered all day.
It's not unhealthy to drink it.
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