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NemiM [27]
3 years ago
14

Balloon has a volume of 600-ml at temperature of 360 K. If the temperature of

Chemistry
1 answer:
Molodets [167]3 years ago
5 0

Answer:

V₂ ≈416.7 mL

Explanation:

This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.

  • V₁ / T₁ = V₂ / T₂

where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.

The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,

  • V₁= 600 mL
  • T₁= 360 K
  • T₂= 250 K

Substitute the values into the formula.

  • 600 mL /360 K = V₂ / 250 K

Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.

  • 250 K * 600 mL /360 K = V₂ / 250 K * 250 K
  • 250 K * 600 mL/360 K = V₂

The units of Kelvin cancel, so we are left with the units of mL.

  • 250 * 600 mL/360=V₂
  • 416.666666667 mL= V₂

Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.

  • 416.7 mL ≈V₂

The volume of the balloon at 250 K is approximately 416.7 milliliters.

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