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tino4ka555 [31]
2 years ago
14

Good evening! Does anyone know this? Earth Science

Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
6 0

The fraction of Earth's radius (6371 km) relative to the thickness of the oceanic (7.5 km) and continental crust (35 km) is 0.12 and 0.55, respectively.    

What we know:

  • The average radius of Earth (E) = 6371 km
  • The average thickness of oceanic crust (O) = 7.5 km
  • The average thickness of continental crust (C) = 35 km

We need to convert all the above units from kilometers to miles:

E = \frac{0.6214 mi}{1 km}*6371 km = 3958.9 mi

O = \frac{0.6214 mi}{1 km}*7.5 km = 4.7 mi

C = \frac{0.6214 mi}{1 km}*35 km = 21.7 mi

Now, we can calculate the fraction of Earth's radius relative to each type of crust, with the given equation:

X = \frac{avg. \: thickness}{avg. \: radius} \times 100

  • <u>For the oceanic crust (O)</u>:

X = \frac{4.7 mi}{3958.9 mi}\times 100 = 0.12

  • <u>For the continental crust (C)</u>:

X = \frac{21.7 mi}{3958.9 mi}\times 100 = 0.55

Therefore, the fraction of Earth's radius relative to the oceanic and continental crust is 0.12 and 0.55, respectively.

You can see another example of calculation of fractions of Earth's radius here: brainly.com/question/4675868?referrer=searchResults

I hope it helps you!

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Answer:

Contributes to the membrane potential.

Explanation:

Sodium-potassium pump: In cellular physiology, a protein which is identified in many cells that helping in to maintain the higher concentration of potassium ions inside than that is in the surrounding medium and maintain the lower concentration of sodium ions inside than that of the surrounding medium.

This unbalanced charge transfer contributes in the separation of charge across the cell membrane. Sodium-potassium pump is known for important contributor to action potential which is produce by nerve cells.

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3 years ago
A carbon skeleton is covalently bonded to both an amino group and a carboxyl group. When placed in water it ____
kotykmax [81]

Answer:

The correct option is: (D) would function as both an acid and a base

Explanation:

A carbon skeleton bonded to a amino group as well as a carboxyl group, will behave as an acid in basic medium and base in acidic medium. This is because the carboxyl group present in the compound will release a proton in basic medium and the amino group will accept a proton in the acidic medium.

<u>Therefore, a carbon skeleton which is covalently bonded to a carboxyl and amino group will behave as both acid and base.</u>

8 0
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Using the Rydberg formula, calculate the initial energy level when an electron in a hydrogen atom transitions into n= 2 and emit
EleoNora [17]

Answer:

1

Explanation:

Using the Rydberg formula as:

\frac {1}{\lambda}=R_H\times Z^2\times (\frac {1}{n_{1}^2}-\frac {1}{n_{2}^2})

where,

λ is wavelength of photon

R = Rydberg's constant (1.097 × 10⁷ m⁻¹)

Z = atomic number of atom

n₁ is the initial final level and n₂ is the final energy level

For Hydrogen atom, Z= 1

n₂ = 2

Wavelength = 410.1 nm

Also,

1 nm = 10⁻⁹ m

So,

Wavelength = 410.1 × 10⁻⁹ m

Applying in the formula as:

\frac {1}{410.1\times 10^{-9}}=1.097\times 10^7\times 1^2\times (\frac {1}{n_{1}^2}-\frac {1}{2^2})

Solving for n₁ , we get

n₁ ≅ 1

3 0
3 years ago
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When heated, calcium carbonate goes through a chemical reaction, and produces calcium oxide (quick lime) powder and carbon
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Answer:

Carbon dioxide is produced, and as a gas, it was not captured to measure its mass.

Explanation:

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3 years ago
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Octane has a density of 0.703 g/ml. Calculate the mass of CO2(g) produced by burning one
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The mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

The given parameters:

  • <em>Density of the octane, ρ = 0.703 g/ml</em>
  • <em>Volume of octane, v = 3.79 liters</em>

<em />

The mass of the octane burnt is calculated as follows;

m = \rho V\\\\m = 0.703 \ \frac{g}{ml} \times 3.79 \ L \ \frac{1000 \ ml}{L} \\\\m = 2,664.37 \ g

The combustion reaction of octane is given as;

2C_8H_{18} +  \ 25O_2 \ --> \ 16CO_2 \ + \ 18H_2O

From the reaction above:

228.46 g of octane -------------------> 704 g of  CO₂ gas

2,664.37 of octane --------------------> ? of CO₂ gas

= \frac{2,664.37 \times 704}{228.46} \\\\= 8,210.3 \ g\\\\= 8.21 \ kg

Thus, the mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

Learn more about combustion of organic compounds here: brainly.com/question/13272422

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