To do your homework correctly you should (5 points)

Suppose you apply a flame to heat 1 liter of water and its temperature rises by 3 C. If you apply the same flame for the same le

kykrilka [37]

Answer:1 $^{0}C$

Explanation:

Let the heat given by flame be $h$ .

Let $m_{1}$ be the mass of water in case 1.

Let $m_{2}$ be the mass of water in case 2.

Let Δ $T_{1}$ be the temperature difference in case 1.

Let Δ $T_{2}$ be the temperature difference in case 2.

Let $V_{1}$ be the volume of water in case 1.

Let $V_{2}$ be the volume of water in case 2.

Let $d$ be the density of water.

Let $s$ be the specific heat of water.

Given,

$V_{1}=1L\\V_{2}=3L\\$

Δ $T_{1}=3^{0}C$

Since the same heat is given to water in both the cases,

$h=m_{1}s$ Δ $T_{1}$

$h=m_{2}s$ Δ $T_{2}$

So, $m_{1}s$ Δ $T_{1}$ = $m_{2}s$ Δ $T_{2}$

Since mass is product of volume an density,

$V_{1}ds$ Δ $T_{1}$ = $V_{2}ds$ Δ $T_{2}$

$1\times d\times s\times 3=3\times d\times s\times$ Δ $T_{2}$

So,Δ $T_{2}=1^{0}C$

4 0

3 years ago

A 4.5 kg box slides down a 4.3-m-high frictionless hill, starting from rest, across a 2.0-m-wide horizontal surface, then hits a

Rainbow [258]

Answer:

speed before reaching rough surface = 9.18 m/s

speed before hitting spring = 8.70 m/s

spring compression = 82 cm

number of complete trip = 9

Explanation:

Lets say

Position 1: On top of hill

Position 2: down the hill

Position 3: after the rough surface

Position 4: after hitting the spring

We'll strictly use conservation of energy for this equation

Potential energy on top of energy is full converted into kinetic energy down the hill (since surface is frictionless)

Hence, PEg1 = KE2

mgh = (1/2)mv2^2

(4.5)(9.8)(4.3) = (1/2)(4.5)v2^2

189.63 = (1/2)(4.5)v2^2

v2^2 = 2(9.8)(4.3) = 84.28

v2 = sqrt(84.28) = 9.18 m/s

After down the hill, it passes a rough surface. So some of the energy is loss due to friction forces

Friction force, Ff = u (coeff of kinetic friction ) x N (normal force)

Normal force, N = weight of box = mg = 4.5 x 9.8

Ff = 0.22 x 4.5 x 9.8

Work done / Energy loss = Wf = Ff x d (distance)

Wf = 0.22 x 4.5 x 9.8 x 2 = 19.404

Energy after passing the rough surface is totally kinetic energy

KE3 = KE2 - Wf = 189.63 - 19.404 = 170.226

speed after rough surface,

(1/2)mv3^2 = 170.226

v3 = sqrt((2 x 170.226)/4.5) = 8.70 m/s

After hitting the spring, all the kinetic energy is converted into potential energy of spring

170.226 = (1/2)kx^2

x^2 = 2 x 170.226 / 510 {note that constant of spring, k = 510}

x^2 = 0.668

x = sqrt(0.668) = 0.82m (82 cm)

To calculate complete trip before the box coming to rest, note that the only place where it loss energy is at the rough surface.

Energy before the first time pass rough surface = 189.63

Energy loss each time passing rough surface = 19.404

189.63 / 19.404 = 9.773 (9 complete with balance of 0.773)

That mean, the box will pass the rough surface 9 complete trip before coming to rest

8 0

3 years ago

A car travelled a distance of 348 km in 6.0 hours. What was it’s speed in (a) km/h and (b) m/sec?

zavuch27 [327]

Answer:

[(a=58)(b=16)] is the homogeneous mixture

3 0

3 years ago

The image shows a wheel that’s wound up and released. The wheel moves up and down as shown. Identify the position of the wheel w

slega [8]

The highest point of the wheel is the position of the wheel when its potential energy is greatest.

<h3>At what position of the wheel potential energy is greatest?</h3>

The position of the wheel when its potential energy is greatest when it is at the highest point because potential energy depends on the height of an object. If the object is at more height then it has more potential energy and vice versa.

So we can conclude that the highest point of the wheel is the position of the wheel when its potential energy is greatest.

Learn more about energy here: brainly.com/question/13881533

#SPJ1

8 0

2 years ago

Compare the geology of Callisto, Ganymede, and Titan.

V125BC [204]

Explanation: Ganymede, Callisto, Titan are the moons of outer planets or gaseous planets which are made up of ice and rock. Callisto is an ice-covered moon and has no inner or outer activity and is considered basically geologically dead. Ganymede has rocky core and shows signs of tectonic activity, including long cracks in the crust and regions of young surface terrain. Titan has active geology of liquid hydrocarbons on the surface, rain back onto the surface and evaporation into the atmosphere. It has similar size, composition and mass to Ganymede and Callisto.

8 0

3 years ago