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Bogdan [553]
3 years ago
5

To do your homework correctly you should (5 points)

Physics
2 answers:
pychu [463]3 years ago
4 0

Answer:

C according to me

Explanation:

ITS HARD

Murrr4er [49]3 years ago
3 0
I believe c but I’m not particularly sure
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Explanation: 12 minutes is 1/5 of an hour. 35/5=7

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Which of the following is equal to the area under a velocity-time graph
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-- The area under a velocity/time graph, between two points in time, is the difference in displacement during that period of time.

-- The area under a speed/time graph, between two points in time, is the distance covered during that period of time.

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An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavie
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To solve the problem it is necessary to apply conservation of the moment and conservation of energy.

By conservation of the moment we know that

MV=mv

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m = lighter mass

v = velocity of lighter mass

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V = \frac{mv}{M}

Also we have that m/M = 1/7 times

On the other hand we have from law of conservation of energy that

W_f = KE

Where,

W_f = Work made by friction

KE = Kinetic Force

Applying this equation in heavier object.

F_f*S = \frac{1}{2}MV^2

\mu M*g*S = \frac{1}{2}MV^2

\mu g*S = \frac{1}{2}( \frac{mv}{M})^2

\mu = \frac{1}{2} (\frac{1}{7}v)^2

\mu = \frac{1}{98}v^2

\mu = \frac{1}{g(98)(5.1)}v^2

Here we can apply the law of conservation of energy for light mass, then

\mu mgs = \frac{1}{2} mv^2

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3 years ago
An object of mass 10.0kg is released at point A, slidesto the bottom of the 30° incline, then collides with ahorizontal massless
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Answer:

Explanation:

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= 10 x 9.8 x 2 = 196 J

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.5 x 10 v² = .5 x 500 x .75²

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b ) kinetic energy of mass at the bottom

= /2 m v²

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= 140.45 J

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= 55.55 J .

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= 140.45  - 55.55

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If h be the height attained

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( We have assumed that loss of energy in return journey will be same due to friction . )

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