This is true. let me know if im wrong.
Answer:
The answer is "
"
Explanation:
Please find the complete question in the attached file.
pi = pressure only at two liquids' devices
PA = pressure atmosphere.
1 = oil density
2 = uncertain fluid density
The pressures would be proportional to the quantity 
cm from below the surface at the interface between both the oil and the liquid.
I just figured this out now.
First you would use the formula
Ephoton= hc/λ and substitute in the value's of plank's constant, the speed of light in a vaccum and the wavelength which will give you the energy in joules. Then you go to the reference table and solve for the energy used between the different levels for Mercury making sure to convert electron volts to jules. In the end the correct answer should be energy level D.
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