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boyakko [2]
3 years ago
12

It took an American football lineman 14 seconds to complete 10 repetitions of a 102 kg bench press. If the bar had to travel 1.4

7 meters each repetition, what was the average power output during this set?
Physics
1 answer:
DIA [1.3K]3 years ago
3 0

Answer:

1050.651 W

Explanation:

m = Mass of bench press = 102 kg

h = Height of lift = 1.47 m

t = Time taken = 14 seconds

g = Acceleration due to gravity = 9.81 m/s²

The work done is

W=mgh\\\Rightarrow W=102\times 9.81\times 1.47\\\Rightarrow W=1470.9114\ J

For 10 times

W=10\times 1470.9114\\\Rightarrow W=14709.114\ J

Power is given by

P=\dfrac{W}{t}\\\Rightarrow P=\dfrac{14709.114}{14}\\\Rightarrow P=1050.651\ W

The power is 1050.651 W

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In a crash test, a 2,500 kg car hits a concrete barrier at 13 m/s2 calculate the amount of force at which the car strikes the ba
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Answer:

32500N

Explanation:

Data obtained from the question include:

m (mass) = 2500 kg

a (acceleration) = 13 m/s2

F (force) =?

Force is the product of mass and acceleration. It is represented mathematically as:

Force = mass x acceleration

F = m x a

With the above formula, the force with which the car strikes the barrier can be obtained as follow:

F = m x a

F = 2500 x 13

F = 32500N

Therefore, the car will strike the barrier with a force of 32500N

8 0
3 years ago
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Stan is driving north on his scooter at 8m/s, accelerates 11m/s (North) in 4s, drives a constant velocity for the next 15s, and
kow [346]

A) Acceleration: a_1 = 0.75 m/s^2, a_2 = 0, a_3 = -1.57 m/s^2

B) The total displacement is 209.5 m north

C) The average velocity is 8.06 m/s north

Explanation:

A)

Acceleration is defined as:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time taken for the velocity to change from u to v

Here we have:

- In the first  segment,

u = 8 m/s north

v = 11 m/s north

t = 4 s

So the acceleration is

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- In the second segment, Stan drives at a constant velocity: so the final velocity is equal to the initial velocity,

u = v

Therefore, the acceleration is zero: a_2 = 0

- In the third segment,

u = 11 m/s (north)

v = 0 (he comes to a stop)

t = 7 s

So the acceleration is

a=\frac{0-11}{7}=-1.57 m/s^2

And the negative sign means the acceleration is south, opposite to the direction of motion.

B)

In a uniformly accelerated motion, the displacement can be calculated as:

s=ut+\frac{1}{2}at^2

where

u is the initial velocity

a is the acceleration

t is the time

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u = 0\\a = 0.75 m/s^2\\t=4 s

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s_1 = 0+\frac{1}{2}(0.75)(4)^2=6 m

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u = 11 m/s\\a = 0\\t=15 s

So the displacement is

s_2 = (11)(15)+0=165 m

- For the third segment, we have

u = 11\\a = -1.57 m/s^2\\t=7 s

So the displacement is

s_3 = (11)(7)+\frac{1}{2}(-1.57)(7)^2=38.5 m

So the total displacement is:

s = 6 m + 165 m + 38.5 m = 209.5 m

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C)

The average velocity is given by:

v=\frac{d}{t}

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d is the total displacement

t is the total time

Here we have:

d = 209.5 m

t = 26 s

Therefore, the average velocity is

v=\frac{209.5}{26}=8.06 m/s (north)

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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3 years ago
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Answer and Explanation:

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