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boyakko [2]
3 years ago
12

It took an American football lineman 14 seconds to complete 10 repetitions of a 102 kg bench press. If the bar had to travel 1.4

7 meters each repetition, what was the average power output during this set?
Physics
1 answer:
DIA [1.3K]3 years ago
3 0

Answer:

1050.651 W

Explanation:

m = Mass of bench press = 102 kg

h = Height of lift = 1.47 m

t = Time taken = 14 seconds

g = Acceleration due to gravity = 9.81 m/s²

The work done is

W=mgh\\\Rightarrow W=102\times 9.81\times 1.47\\\Rightarrow W=1470.9114\ J

For 10 times

W=10\times 1470.9114\\\Rightarrow W=14709.114\ J

Power is given by

P=\dfrac{W}{t}\\\Rightarrow P=\dfrac{14709.114}{14}\\\Rightarrow P=1050.651\ W

The power is 1050.651 W

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An empty rubber balloon has a mass of 0.0120 kg. The balloon is filled with helium at 0°C, 1 atm pressure, and a density of 0.17
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a) F_b = 6.62 N

b) F_net = 5.583 N

Explanation:

Given:

- Conditions of He gas:  T = 0 C , P = 1 atm , ρ = 0.179 kg/m^3

- The mass of balloon m = 0.012 kg

- The radius of balloon r = 0.5 m

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a)What is the magnitude of the buoyant force acting on the balloon?

b)What is the magnitude of the net force acting on the balloon?

Solution:

- The buoyant force F_b acting on the balloon is equal to the weight of the air it displaces.The mass of the displaced air ρ*V is the volume of the balloon times the density of the. Multiplying that by acceleration due to gravity gives its weight.

                                 F_b = ρ*V*g

                                 F_b = 4*ρ*g*pi*r^3 / 3

                                 F_b = 4*1.29*9.81*pi*.5^3 / 3

                                 F_b = 6.62 N

- The net force will be the difference between the balloon’s weight and the buoyant force. The weight of the balloon is the density of the helium times the volume of the balloon added to the mass of the empty balloon.

                                 F_g = ρ*V*g + m*g

                                 F_g = 4*ρ*g*pi*r^3 / 3 + 0.012*9.81

                                 F_g = 4*0.179*9.81*pi*.5^3 / 3 + 0.012*9.81

                                 F_g = 1.037 N

- The net force is the difference between weight and buoyant force

                                F_net = F_g - F_b

                                F_net = 6.62 - 1.037

                                F_net = 5.583 N

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