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gladu [14]
3 years ago
15

a rifle is used during the biathlon event in the Olympics the rifle has a mass of 2.5 kg the bullet has amass of 0.02 kg after t

hat shot the bullet travels at a speed of 525 m/s what is the total momentum of the rifle bullet system before the bullet is shot?
Physics
2 answers:
lilavasa [31]3 years ago
8 0

Answer:

the momentum of the system must be ZERO just before the bullet is shot

Explanation:

As we know that initially the bullet is inside the gun with stationary condition

So here we can say that gun and bullet was both at rest initially

so we have

P = m_1v_1 + m_2v_2

since both are at rest so we have

v_1 = v_2 = 0

so total momentum of the system will be

P = 0

So the momentum of the system must be ZERO just before the bullet is shot

Nataliya [291]3 years ago
6 0
The momentum before is zero because nothing is moving. Note that because momentum is a conserved vector, the total momentum after the shot is also zero. You just have to add the products of mass and velocity in opposite directions. So the answer is zero
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Which of the following represents a possible magnitude for the force of static friction when Xavier applied 72.1 Newtons of forc
lana66690 [7]

The possible magnitude for the force of static friction on the stationary cart is 72.1 N.

The given parameters:

  • <em>Applied force on the cart, F = 72.1 N</em>

<em />

Based on Newton's second law of motion, the force applied to object is directly proportional to the product of mass and acceleration of the object.

F = ma

Static frictional force is the force resisting the motion of an object at rest.

\Sigma F = 0\\\\F -F_f = 0

where;

F_f is the frictional force

F= F_f \\\\72.1 = F_f\\\\F_f = 72.1\  N

Thus, the possible magnitude for the force of static friction on the stationary cart is 72.1 N.

Learn more about Newton's second law of motion: brainly.com/question/25307325

8 0
2 years ago
A tall cylinder contains 30 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until t
Anastaziya [24]

Answer:

The gauge pressure is  P_g  =  2058 \ P_a

Explanation:

From the question we are told that

       The height of the water contained is  h_w  =  30 \ cm  =  0.3 \ m

        The height of liquid in the cylinder is  h_t  =  40 \ cm  = 0.4 \ m

       

At the bottom of the cylinder the gauge pressure is  mathematically represented as

        P_g  =  P_w + P_o

Where  P_w is the pressure of water which is mathematically represented as

      P_w  =  \rho_w  *  g * h_w

Now  \rho_w is the density of water with a constant values of  \rho_w  = 1000 \ kg /m^3

   substituting values

      P_w  = 1000 *  9.8 *  0.3

     P_w  =  2940 \  Pa

While P_o is the pressure of oil which is mathematically represented as

          P_o  =  \rho_o *  g *  (h_t -h_w )

Where \rho _o is the density of oil with a constant value

         \rho _o  = 900 \ kg / m^3

substituting values

       P_o  =  900 *  9.8 * (0.4 - 0.3)

       P_o  =  882 \ Pa

Therefore

      P_g  =  2940 - 882

      P_g  =  2058 \ P_a

6 0
3 years ago
What does the electric field strength tell about the electric firld?
Solnce55 [7]

Answer:

Explanation:

The region around a charged particle where another charged particle experiences a force of attraction or repulsion is called electric field.

The strength of electric field is defined as the force experienced by the unit positive test charge.

E = F / q

Electric field strength is a vector quantity and it is measured in newton per coulomb.

Where, F is the force of attraction or repulsion between the two charges and q is the test charge on which the electric field strength is to be calculated.

The strength of electric field is more if the field is strong. It means more be the electric field strength at a point more be the electric field.

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In which of the following is positive work done by a person on a suitcase
MrRa [10]

pendajo sMh so stupid

4 0
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Mademuasel [1]
The equation of D = m/V

Where D = density
m = mass
and V = volume

We are solving for V, so with the manipulation of variables we multiply V on both sides giving us 
V(D) = m 
now we divide D on both sides giving us
V = m/D 

We know our mass which is 600g and our density is 3.00 g/cm^3
so
V = 600g/3.00g/cm^3 = 200cm^3  or 200mL

a cubic centimeter (cm^3) is one of the units for volume. It's exactly like mL. 1 cm^3 = 1 mL
 
If you wish to change it to L, you'd have to convert. 
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