Force (F)=Mass (m)×Acceleration (a).
∴F=ma.
∴F=(2kg)×(3ms2).
∴F=6kgms2=6 Newton. =6N.
Answer:
497.6 N
Explanation:
From the question,
The net force on the skydiver = weight of the skydiver- the resistive force of air
F' = W-F...................... Equation 1
Where W = weight of the skydiver, F = resistive force of air.
But,
W = mg................ Equation 2
Where m = mass of the skydiver, g = acceleration due to gravity.
Substitute equation 2 into equation 1
F' = mg-F............ Equation 3
Given: m = 87 kg, F = 355 N, g = 9.8 m/s²
Substitute these values into equation 3
F' = 87(9.8)-355
F' = 852.6-355
F' = 487.6 N
Same formula as the last question. x = vt + (1/2)at^2. In this case, v = 0, t = 12, and a = 2.0. Plug in the values and solve for x (which is change in position)
x = (0)(12) + (1/2)(2.0)(12^2)
x = (1/2)(2.0)(144)
x = (1)(144)
x = 144
So the car will travel 144 meters in 12 seconds.