Answer:
Displacement: 6.71 m, Direction: 63.4 degrees north of east
Explanation:
In the attached image we can aprecciate each one of the movements of the parade. Let's say that the parade started from the origin (point (0,0)) then it moves to the east 4 blocks it means now the parade is located at point (4,0).
Then the parade went to the south three blocks, so it moves to the coordinate (4,-3). After this the parade went to the west one block so the new coordinate point is (3, -3).
And finally the movement of the 0 parade was 9 blocks to the north. It means the final point is now (0,9) - (3,-3) = (3,6)
And the displacement will be defined by the folliwing vector operation:
We know that the magnitude of the displacement vector is defined by the phytagoras theorem
And the angle will be defined by:
tan(beta)=3/6
beta = tan^-1(6/3)
beta = 63.43°
The initial velocity of the cat is 56.6 m/s
Explanation:
The motion of the cat is a projectile motion, consisting of:
- a uniform horizontal motion with constant velocity
- a vertical accelerated motion with constant acceleration (free fall)
We start by analyzing the vertical motion, to find the time it takes for the cat to reach the ground. We use the following suvat equation:
where we have (choosing downard as positive direction)
s = 125 m is the vertical displacement of the cat
u = 0 is the initial vertical velocity
t is the time taken to reach the ground
is the acceleration of gravity
Solving for t, we find
Now we can analzye the horizontal motion. Since the motion is uniform and the horizontal velocity is constant, it is given by
where
d = 286 m is the horizontal distance travelled
t = 5.05 s is the time taken
Solving the equation,
Learn more about projectile motion:
brainly.com/question/8751410
#LearnwithBrainly
Using the equation v(average)=x traveled/time
v = 100/2.5
You get 40 kilometers per hour
Hope this helped!
Answer:
No.
Explanation:
We shall solve this problem by calculating the resolving power of eye for given wavelength
Resolving Power of eye = \frac{1.22\lambda }{D}
Where λ is wave length of light and D is diameter of eye.
λ is 600 nm and D is 3.5 mm . Put these values in the given formula
Resolving Power = \frac{1.22\times 600\times 10^{-9} }{3.5\times 10^{-3}}\\
=209.14 \times 10^{-6}radian
From the formula
Φ = \frac{L}{D}[/tex]
Where Ф is resolving power . If L be distance between two points that can be resolved at distance D. D is 6 km or 6000 m .
209.14 \times 10^{-6}=\frac{L}{6000}\\
L= 1.254 m
So minimum distance that can be resolved is 1.254 m.
That depends on what quantity is graphed.
It also depends on what kind of acceleration is taking place ...
continuous change of speed or continuous change of direction.
-- If the graph shows speed vs time, and the acceleration is a change
in speed, then the graph is a connected series of straight-line pieces.
Each straight piece slopes up if speed is increasing, or down if speed
is decreasing.
-- If the graph shows speed vs time, and the acceleration is a change in
direction only, then the graph is a straight horizontal line, since speed is
constant.
-- If the graph shows direction vs time, and the acceleration is a change
in speed only, then the graph is a straight horizontal line, since direction
is constant.
-- If the graph shows direction vs time, and the acceleration is a change
in direction, then the graph is a connected series of pieces of line.
Each piece may be straight if the direction is changing at a constant rate,
or curved if the direction is changing at a rate which grows or shrinks.
Each piece may slope up if the angle that defines the direction is growing,
or may slope down if the angle that defines the direction is decreasing.
-- If the graph shows distance vs time, and the acceleration is a
change in speed, then the graph is a connected series of pieces
of curves. Each piece curves up if speed is increasing, or down if
speed is decreasing.
-- If the graph shows distance vs time, and the acceleration is a change
in direction only, then the graph is a straight line sloping up, since speed
is constant.
