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2 years ago

2Fe(OH)3 Fe2O3+3H2O how many grams of Fe2O3 are produced if 10.7 grams of Fe (OH)3 react in this way

Chemistry

1 answer:

sasho [114]2 years ago

3 0

Answer: 7.98 grams of $Fe_2O_3$ are produced if 10.7 grams of $Fe(OH)_3$ are reacted.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Putting values in equation 1, we get:

$\text{Moles of} Fe(OH)_3=\frac{10.7g}{106.87g/mol}=0.100mol$

The chemical equation for the reaction is

$2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O$

By Stoichiometry of the reaction:

2 moles of $Fe(OH)_3$ produce = 1 mole of $Fe_2O_3$

So, 0.100 moles of $Fe(OH)_3$ produce= $\frac{1}{2}\times 0.100=0.05mol$ of $Fe_2O_3$

Mass of $Fe_2O_3$ = $moles\times {\text{Molar Mass}}=0.05mol\times 159.69g/mol=7.98g$

Hence 7.98 grams of $Fe_2O_3$ are produced if 10.7 grams of $Fe(OH)_3$ are reacted.

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3 years ago

The voltage generated by the zinc concentration cell described by the line notation Zn ( s ) ∣ ∣ Zn 2 + ( aq , 0.100 M ) ∥ ∥ Zn

Oxana [17]

Answer:

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Explanation:

We need to calculate the Zn²⁺ concentration at the cathode where reduction occurs which is the right side in the expression:

Zn2+(aq,0.100 M) ‖ Zn2+(aq,? M) | Zn(s)

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The driving force is the difference in concentration and E the electromotive force will be given by

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Plugging the value for E and knowing Eº is cero because we have the same electrodes, we have

17.0 x 10⁻³ = 0 - 0.0592 log 0.100/ X =

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4 0

3 years ago

What is the resistance of a 150 W lightbulb connected to a 24 V voltage source?

Luda [366]

Answer:

3.84 Ω

Explanation:

From the question given above, the following data were obtained:

Electrical power (P) = 150 W

Voltage (V) = 24 V

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Recall:

V = IR

Divide both side by R

I = V/R

P = V/R × V

P = V² / R

Where:

P => Electrical power

V => Voltage

I => Current

R => Resistance

With the above formula (i.e P = V²/R), we can calculate resistance as illustrated below:

Electrical power (P) = 150 W

Voltage (V) = 24 V

Resistance (R) =?

P = V²/R

150 = 24² / R

150 = 576 / R

Cross multiply

150 × R = 576

Divide both side by 150

R = 576 / 150

R = 3.84 Ω

Thus, the resistance is 3.84 Ω

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3 years ago

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