Answer: C₇H₁₄ + 7O₂ → 7CO + 7H₂O
Explanation:
- For any equation to be balanced the number of (C, H, and O) atoms in the reactants side should be the same in the products side.
- The first choice is wrong because it is unbalanced equation that the reactants side has 22 O atoms and in the products side there is 14 O atoms.
- The second choice is wrong because the incomplete combustion of heptene results CO and/or CO₂ and H₂O.
- The third choice is the right answer that it has 7 atoms of C, 14 atoms of H, and 14 atoms of O in both reactants and products sides.
- The fourth choice is wrong because the combustion of heptene occurs in O₂ not in O.
Explanation:
2 ClO2 (aq) + 2OH- (aq)→ ClO3- (aq) + ClO2- + H2O (l)
The data is given as;
Experiment [ClO2] (M) [OH-] (M) Initial Rate (M/s)
1 0.060 0.030 0.0248
2 0.020 0.030 0.00276
3 0.020 0.090 0.00828
a) Rate law is given as;
Rate = k [ClO2]^x [OH-]^y
From experiments 2 and 3, tripling the concentration of [OH-] also triples the rate of the reaction. This means the reaction is first order with respect to [OH-]
From experiments 1 and 2, when the [ClO2] decreases by a factor of 3, the rate decreases by a factor of 9. This means the reaction is second order with respect to [ClO2]
Rate = k [ClO2]² [OH-]
b. Calculate the value of the rate constant with the proper units.
Taking experiment 1,
0.0248 = k (0.060)²(0.030)
k = 0.0248 / 0.000108
k = 229.63 M-2 s-1
c. Calculate the rate when [ClO2] = 0.100 M and [OH-] = 0.050 M.
Rate = 229.63 [ClO2]² [OH-]
Rate = 229.63 (0.100)²(0.050)
Rate = 0.1148 M/s
The correct answer is this one: "the number of electrons that are involved in the bonding of the molecule." Lewis structures help us understand the number of electrons that are involved in the bonding of the molecule. It also helps us know the shape of the molecule, its reactivity and its interaction with other molecules.
Answer: Tens place.
Step-by-step explanation: hmm wait one moment
