Which is one way that scientist communicate the result of an experiment

A natural sample of boron consists of two isotopes

amid [387]

Boron: isotope data. Both isotopes ofBoron, B-10 and B-11, are used extensively in the nuclear industry. B-10 is used in the form of boric acid as a chemical shim in pressurized water reactors while in the form of sodium pentaborate it is used for standby liquid control systems in boiling water reactors

7 0

3 years ago

Tyserium (ty) consists of two isotopes. one isotope has a mass of 331 amu and is 35.0 % abundant. the other isotope is 337 amu a

RSB [31]

The atomic masses written for every element in the periodic table is the average atomic weight that is calculated from the element's isotopes. The formula would be:

Average Atomic Weight = ∑(Isotope Mass×Relative Abundance)
Substituting the values:
Average Atomic Weight = (331 amu×0.35) + (337 amu×0.65)
Average Atomic Weight = 334.9 amu

8 0

4 years ago

Read 2 more answers

Which of the following molecules can be used in catabolic reactions to generate the carbon backbones required for gluconeogenesi

sleet_krkn [62]

Answer:

The correct option is A

Explanation:

Some amino acids, called glucogenic amino acids, when catabolized convert there carbon backbones to tricarboxylic acid (TCA) cycle intermediates. These intermediates can be subsequently metabolized into carbon dioxide and water with the release of ATP or the formation of glucose (known as gluconeogenesis.

<u>All amino acids (with the exception of leucine and lysine) are glucogenic and can thus generate the carbon backbones required for gluconeogenesis</u>. Thus, the correct option is a.

3 0

3 years ago

A purple rock as a mass of 316 grams and a density of 5.9 g/mL. Determine the volume of this rock in mL.

MakcuM [25]

Answer:

The answer is

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass of rock = 316 g

density = 5.9 g/mL

The volume of the rock is

$volume = \frac{316}{5.9} \\ = 53.5593220...$

We have the final answer as

Hope this helps you

5 0

3 years ago

An element has an average atomic mass of 1.008 amu. It consists of two isotopes , one having a mass of 1.007 amu, and one having

dimulka [17.4K]

Answer:

The most abundant isotope is 1.007 amu.

Explanation:

Given data:

Average atomic mass = 1.008 amu

Mass of first isotope = 1.007 amu

Mass of 2nd isotope = 2.014 amu

Most abundant isotope = ?

Solution:

First of all we will set the fraction for both isotopes

X for the isotopes having mass 2.014 amu

1-x for isotopes having mass 1.007 amu

The average atomic mass is 1.008 amu

we will use the following equation,

2.014x + 1.007 (1-x) = 1.008

2.014x + 1.007 - 1.007 x = 1.008

2.014x - 1.007x = 1.008 - 1.007

1.007 x = 0.001

x= 0.001/ 1.007

x= 0.0009

0.0009 × 100 = 0.09 %

0.09 % is abundance of isotope having mass 2.014 amu because we solve the fraction x.

now we will calculate the abundance of second isotope.

(1-x)

1-0.0009 = 0.9991

0.9991 × 100= 99.91%

6 0

3 years ago