Answer: This was because the experiment showed that a substance could emit radiation even while it was not exposed to light.
Answer:
Iffdldzdosodolzf cvbvxhmnvhihsoszüf
C6H12O + 6OC2 + 6H2O + energy
<span>because p6 will be the group 8. You have to count the 2 electrons from the "s" block that are Group I and Group II
Group I s1
Group II s2
Group III s2 p1
Group IV s2 p2
Group V s2 p3
Group VI s2 p4
Group VII s2 p5
Group VIII s2 p6</span>
Answer is: Kp = 66,586.
Chemical reaction: PCl₃(g) + Cl₂(g) ⇔ PCl₅(g).
Kp - equilibrium constants expressed in terms of partial pressures of gases.
Kp = p(PCl₅) ÷ p(PCl₃) · p(Cl₂). p-partial pressure.
Kp = 1,67 atm ÷ 0,132 atm · 0,190 atm
Kp = 66, 586 1/atm. Favors product.
