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wlad13 [49]
3 years ago
8

When potassium chlorate decomposes to potassium chloride and oxygen gas is it a physical or chemical change?

Chemistry
1 answer:
scZoUnD [109]3 years ago
4 0
It is an example of a Chemical change.
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A white crystalline salt conducts electricity when it is melted and when it dissolves in water.
sergeinik [125]

Answer: Option (a) is the correct answer.

Explanation:

Ionic salts are defined as the salts which tend to contain ionic bonds as there occurs transfer of electrons between its combining atoms.

So, when an ionic salt melts or it is dissolved in water then it will dissociate into its respective ions and as electricity is the flow of electrons or ions. Hence, this salt is then able to conduct electricity.

As covalent compounds are insoluble in water so, they do no dissociate into ions. Hence, they do not conduct electricity.

Similarly, metallic and network solids do not dissociate into ions either when melted or dissolved in water. Therefore, they also do not conduct electricity.

Thus, we can conclude that when a white crystalline salt conducts electricity when it is melted and when it dissolves in water then this bond is of ionic type.

7 0
3 years ago
Define the term diffusion
maw [93]

Answer:

Spreading, like dispersing.

Explanation:

7 0
3 years ago
Read 2 more answers
Any help with these questions would help i'm lost
SSSSS [86.1K]

Answer:

1.  31.25 mL

2.  1.98 g/L

3.  0.45 g/mL

Explanation:

For each of the problems, you need to perform unit conversions.  You need to use the information given to you to convert to a specific unit.

1.  You need volume (mL).  You have density (g/mL) and mass (g).  Divide mass by density.  You will cancel out mL and be left with g.

(50.0 g)/(1.60 g/mL) = 31.25 mL

2.  You are given grams and liters.  You need to find density with units g/L.  This means that you have to divide grams by liters.

(0.891 g)/(0.450 L) = 1.98 g/L

3.  You have to find density again but this time with units g/mL.  Divide the given mass by the volume.

(10.0 g)/(22.0 mL) = 0.45 g/mL

5 0
3 years ago
Show, in a step by step fashion, your calculations to determine the percent
marusya05 [52]

The percent  by volume of a solution : 19.23%

<h3>Further explanation</h3>

Given

50 ml of ethanol

210  ml of water

Required

The percent  by volume of a solution

Solution

Percent Volume (% v/v) : volume (ml) of solute/100 ml of solution ⇒ ratio of the volume of the solute to total volume of the solution

\tt \%solute(v/v)=\dfrac{solute~volume}{solution~volume}\times 100\%

solute= Ethanol

solvent=water

Solution = solute+solvent

Total volume of the solution :

\tt =volume~of~Ethanol+solume~of~water\\\\=50~ml+210~ml\\\\=260~ml

Percent by volume :

\tt \%volume=\dfrac{50}{260}\times 100\%\\\\\%volume=19.23\%

8 0
3 years ago
Include two kinds
MatroZZZ [7]

Answer:

Explanation:

Ionic bond:

It is the bond which is formed by the transfer of electron from one atom to the atom of another element.  

Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.

For example:

Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.  Both atoms are joint together by electrostatic interaction and ionic compound sodium chloride is formed.

Covalent bond:

It is formed by the sharing of electron pair between bonded atoms.  

The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive and both bonded atoms connected together through covalent bond.

8 0
3 years ago
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