Answer:
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The atomic weight of carbon dioxide is about 12.011 + 15.999 + 15.999 = 44.009.
44.009 grams of CO2 = 1 mole of CO2 CO2 = Carbon dioxide
25 ÷ 44.009 ≈ 0.568
About 0.568 moles of CO2
5.75g
Explanation:
Given parameters:
Number of atoms = 1.505 x 10²³atoms
let us find the number of moles and mass of this atom.
Solution:
The mole is convenient unit for reporting measurements in chemistry. It allows us to make mathematical calculations:
one mole of substance contains 6.02 x 10²³atoms
Number of moles of Na given =
= 0.25moles
Mass of Na atom given = number of moles x molar mass
Molar mass of Na= 23g/mole
Mass of Na = 0.25 x 23 = 5.75g
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Answer:
3 : 1
Explanation:
The following data were obtained from the question:
Initial temperature (T₁) = T
Initial pressure (P₁) = P
Final temperature (T₂) = 3T
Final pressure (P₂) =..?
Since the volume is constant, we shall use the following formula P₁ /T₁ = P₂ /T₂ to obtain the final pressure. This is illustrated below:
P₁ /T₁ = P₂ /T₂
P/T = P₂ /3T
Cross multiply
T × P₂ = P × 3T
Divide both side by T
P₂ = P × 3T /T
P₂ = P × 3
P₂ = 3P
Therefore, the final pressure is tripled.
Finally, we shall determine the ratio of the final pressure to the initial pressure as follow:
Initial pressure (P₁) = P
Final pressure (P₂) = 3P
Final pressure (P₂) : Initial pressure (P₁)
P₂ : P₁ => 3P/P
P₂ : P₁ => 3 : 1
Therefore, the ratio of the final pressure to the initial pressure is 3 : 1