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Gelneren [198K]
3 years ago
7

What is the ending of the electron configuration of each element in group 4?

Chemistry
1 answer:
bogdanovich [222]3 years ago
6 0
<span>because p6 will be the group 8. You have to count the 2 electrons from the "s" block that are Group I and Group II Group I s1 Group II s2 Group III s2 p1 Group IV s2 p2 Group V s2 p3 Group VI s2 p4 Group VII s2 p5 Group VIII s2 p6</span>
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What is the molarity of a solution prepared by dissolving 10.7 g NaI in 0.250 L?0.0714
hjlf

Answer:0.286M

Explanation:

10.7g / 149.89g/mol×0.25L

4 0
3 years ago
Read 2 more answers
A non-magnetized metal object can be magnetized with a stronger magnet. Explain how this happens on the atomic level.
sergeinik [125]
I believe the atomic level increases hope this helps.

6 0
3 years ago
How can an elements become ion​
Tanzania [10]
When a stable atom gains or loses its electrons then that’s when it becomes the ion.
7 0
3 years ago
I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r
maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P

Now, the moles of Li3P consumed by 15 g of Al2O3:

n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP

Therefore, the total mass of products is:

m_{products}=13g+8.5g\\\\m_{products}=21.5g

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0
3 years ago
Inclined planes reduce the amount of effort needed to move an object, but increases
QveST [7]

Inclined planes reduce the amount of effort needed to move an object, but increases the length of the ramp.

<u>Explanation:</u>

Mechanical advantage is the measure of amount of effort needed to move an object. The mechanical advantage can be calculated as the ratio of length of ramp to the height of ramp for an inclined plane.

As it is known that an object can be easily moved on an inclined plane than on a vertical plane, this is because, the inclined plane provides greater output force. But in that case, the effort required will be reduced with the cost of increasing the distance of the movement of object.

In other terms , the ramp's length of inclined planes has to get increased in order to reduce the amount of effort needed to move an object. This is because as the mechanical advantage has length of the ramp in the numerator, with the increase in numerator value or length value the mechanical advantage will also increase.

8 0
3 years ago
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