All categories

2 years ago

Give a chemical equation for aerobic cellular respiration

1 answer:

5 0

C6H12O + 6OC2 + 6H2O + energy

You might be interested in

Fittoniya [83]

Answer:

At anode - ${Br_2}_{(l)}$

At cathode - ${H_2}_{(g)}$

Explanation:

Electrolysis of NaBr:

Water will exist as:

$H_2O\rightleftharpoons H^++OH^-$

The salt, NaBr will dissociate as:

$NaBr\rightarrow Na^++Br^-$

At the anode, oxidation takes place, as shown below.

${Br^-}_{(aq)}\rightarrow {Br_2}_{(l)}+2e^-$

At the cathode, reduction takes place, as shown below.

$2{H^+}_{(aq)}+2e^-\rightarrow {H_2}_{(g)}$

4 0

2 years ago

Verdich [7]

Water is produce bases and says

6 0

2 years ago

garik1379 [7]

2 atome nitrogen , 1 is correct

5 0

3 years ago

Oksi-84 [34.3K]

gases become more soluble in liquids as the temperature gets higher
<span />

3 0

2 years ago

liraira [26]

Answer:

have just recently learnt the theory of fractional and normal distillations and the basics of maximum and minimum boiling azeotropes.

6 0

2 years ago