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Finger [1]
3 years ago
14

What types of emergency situations could rescue workers be in that would make it difficult for them to get energy to their elect

rical devices?

Chemistry
1 answer:
artcher [175]3 years ago
4 0

Answer:

Large-scale natural disasters

Explanation:

The emergency situation that rescue workers could be in that would make it difficult for them to get energy to their electrical devices is "Large-scale natural disasters"

Large-scale natural disasters are very destructive and devastating. Their impact and effect can range from destruction of infrastructures, properties, social amenities and even ecosystems. When such disasters break out, they destroy things and which leads to difficulty in accessing certain amenities. Rescue workers even find it difficult to access energy for their electrical devices - because there is power outage.

Some of these large-scale natural disasters are earthquakes, tornadoes, hurricanes, floods, etc.

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Hello There!

We will have water (H2O)

So if you drink a glass of water, you drink a glass of H2O.

Hope it helps! :)

GraceRosalia here to help you :)

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2 years ago
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How many grams of NaCl are needed to prepare 50.0 grams of a 35.0% salt solution?​
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3 years ago
What could J. J. Thomson conclude from his experiments? Atoms are mostly empty space. Most of the mass of the atom is concentrat
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atoms must balance positive and negative particles

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2 years ago
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Calculate the average atomic mass of element X using the table below. Then use the periodic table to identify the element. Separ
Ksenya-84 [330]

Answer:

126.8, Iodine

Explanation:

  • mass ×abundance/100
  • (126.9045×80.45/100)+(126.0015×17.23/100)+(128.2230×2.23/100)
  • 102.1+21.7+3=126.8

<em>IODINE</em><em> </em><em>has</em><em> </em><em>an</em><em> </em><em>atomic</em><em> </em><em>mass</em><em> </em><em>of</em><em> </em>126.8 or 126.9

4 0
2 years ago
Calculate the molarity of a solution with 233.772g sodium chloride dissolved in 2,000mL of water
LekaFEV [45]

Answer:

The molarity is 2M

Explanation:

First , we calculate the weight of 1 mol of NaCl:

Weight 1mol NaCl= Weight Na + Weight Cl= 23 g+ 35, 5 g= 58, 5 g/mol

58,5 g---1 mol NaCl

233,772 g--------x= (233,772 g x1 mol NaCl)/58,5 g= 4 mol NaCl

<em>A solution molar--> moles of solute in 1 L of solution:</em>

2 L-----4 mol NaCl

1L----x0( 1L x4mol NaCl)/4L =2moles NaCl---> 2 M

3 0
2 years ago
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