1.65g MgO = 1g Mg
1.65 - 1 = 0.65 g of O in MgO
solve it using proportion:
1g Mg / 0.65g O = x (g) Mg / 16g O
or 1 / 0.65 = x / 16
24.6 g is the answer.
if 1 gram of oxygen requires 1.65 grams of Mg
then 16 grams of oxygen will require 16 ( 1.65) or 26.4 grams.
False. It is a fluid as it is in its liquid state possessing qualities of a liquid just that it is viscious
Answer:
(2R,3S)-2-chloro-3,5-dimethylhexane
Explanation:
As first step we have the <u>attack of the OH group</u> to the P atom in the PCl3 and one of the Cl atoms would leave. Then we will have a <u>rearrangement</u> to produce a <u>double bond </u>with the oyxgen on the OH. Finally the Cl produced will a<u>ttack the carbon</u> in a <u>Sn2 substitution reaction</u> to produce the halide with an <u>opposite configuration</u>.