Atoms of an element have the same atomic number but different mass numbers because the atomic number only contains the amount of protons in an element.
Atoms of the same element that have different mass numbers are called isotopes.
With (AZ)X, the A is the number of protons, the Z is the number of neutrons, and the X is the electrons.
0.15*240=36 ml of alcohol in <span>240 ml of a 15% alcohol mixture
0.4x = </span>ml of alcohol in x ml of a 40% alcohol mixture
0.2(x+240)= ml of alcohol in (x+240) ml of a 20% alcohol mixture
0.15*240 + 0.4x = 0.2(x+240)
36+0.4x=0.2x+48
0.2x = 12
x=12/0.2=120/6=20 ml of a 40% alcohol mixture
Answer:
107.64L
Explanation:
V= Volume in Liter
T= Temp in Kelvin (degrees celcius + 275)
N= # Mols
P= Pressure
R= Gas Constant for atm is .0821
so
for P
V=NRT/P
(4x,0821x295)/.900=107.64L
Answer:The mechanism of the formation of 4-nitrophenyl phenyl ether include the electrophilic substitution in phenol and the nitration of chlorobenzene.
Explanation:
To prepare the 4-nitrophenyl phenyl ether appropriate equivalent of aqueos NaOH is added to absolute phenol, dissolved gives a Phenoxide ion aqueous and is then added.
After the addition of the appropriate mole of chlorobenzene, to the mixture of HNO3 and H2SO4 is heated under reflux with stirring and exclusion of moisture for 5 hours. The alcohol is distilled off from the reaction mixture to a substantial extent through a 20-cm Vigreux column with stirring and the cooled distillation residue is poured into 100 ml of 5% caustic sodium carbonate; the organic phase is extracted several times with diethyl ether, washed with water, and dried with calcium chloride; the solvent is distilled off, and the residue is fractionated or recrystallized from ethanol. Unchanged phenol can be recovered by acidifying the aqueous alkaline solution and extracting it with ether.
The yield of 4-nitrophenyl phenyl ether 80%, m.p. 40°C; b.p. 286-287 °C; in the presence of HNO3 and H2SO4
Answer:
1)
a) 3.9 mol.
b) The limiting reactant here is HBr that is in a low no. of moles and Al is in excess.
2)
a) 5.45 mol.
b) The limiting reactant here is Si that is in a low no. of moles and N2 is in excess.
3)
a) 2.36 mol.
b) The limiting reactant here is KI that is in a low no. of moles and CuCl2 is in excess.
4)
a) 2.36 mol.
b) The limiting reactant here is O2 that is in a low no. of moles and FeS2 is in excess.
5)
a) 13.24 mol.
b) The limiting reactant here is NH3 that is in a low no. of moles and NO is in excess.
6)
a) 2.71 mol.
b) The limiting reactant here is O2 that is in a low no. of moles and C2H6 is in excess.
7)
a) 7.085 mol.
b) The limiting reactant here is NaOH that is in a low no. of moles and As is in excess.
8)
a) 5.632 mol.
b) The limiting reactant here is H2 that is in a low no. of moles and Au2S3 is in excess.
9)
a) 5.6625 mol.
b) The limiting reactant here is H2O that is in a low no. of moles and CO2 is in excess.
10)
a) 7.905 mol.
b) The limiting reactant here is Fe that is in a low no. of moles and O2 is in excess.
Explanation:
<em>Kindly, find the attached pdf and word files that contain all the deatils and the step by step explanation of all answers.</em>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
pdf
</span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
docx
</span>