Answer:
12.0108408
Explanation:
Denote the element with a letter like say X. Since it has a subscript of 5, then, X5.
Molecular mass=102.133g/mol.
% of X in compound =58.8/100
=0.588
Mass of X in the compound = 0.588*102.133 ( the % of X in compound * molar mass of compound)
= 60.054204
X5=60.054204
Then element X has a mass of 60.054204/5=12.0108408
Answer:
The equation is balanced
Explanation:
NaCl (aq) + AgNO3(aq) ––> AgCl (s) + NaNO3 (aq)
NaCl (aq) + AgNO3 (aq)
Na = 1 , Cl=1 , Ag = 1 , No3= 1
AgCl (s) + NaNO3 (aq)
Ag = 1 , Cl=1 , Na = 1 , No3= 1
The question ask for the percentage of the abundance of galium-69 where there is two isotopes of galium: the 69Ga and the 71Ga. The average atomic mass of gallium is 69.723 amu. So the formula would be <span>69.723amu=(%x)∗(68.926amu)+(1−%x)∗(70.025amu) and the answer to this is 1.58%</span>
