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Alborosie
3 years ago
14

What is the percentage concentration by mass of a solution that contains 0.098 kg of H2SO4 in 500.0 g of H2O?

Chemistry
2 answers:
Setler [38]3 years ago
6 0

Answer: The percentage concentration by mass of a solution that contains 0.098 kg of H_2SO_4 in 500.0 g of H_2O is 16.4%

Explanation:

To calculate the mass percentage ,we use the formula:

\text{Mass percent}=\frac{\text{Mass of} H_2SO_4}{\text{Molar mass of} H_2SO_4+mass of water}\times 100

Mass of H_2SO_4 = 0.098 kg= 98 g

Mass of water = 500 g

Putting values in above equation, we get:

\text{Mass percent}=\frac{98g}{98+500}\times 100=16.4\%

Hence, percentage concentration by mass of a solution that contains 0.098 kg of H_2SO_4 in 500.0 g of H_2O is 16.4%

Arada [10]3 years ago
4 0
Mass of solute  in g :

1 kg ---------- 1000 g
0.098 kg ------ ??

0.098 x 1000 / 1 => 98.0 g

mass of solvent = 500.0 g 

Therefore:

% ( w/w ) = 98.0 / 98.0 + 500.0

% (w/w ) = 98.0 / 598.0

0.163 x 100 =>  16.3 %


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The rate of acceleration of an object is determined by the mass of the object and...
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You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the
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Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate  reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

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= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

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8 0
3 years ago
When Truman walks across the tile floor in his kitchen, the sound of his shoes is loud and sharp. Which of the following best de
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6 0
3 years ago
Table salt contains 39.33 g of sodium per 100 g of salt. The U.S. Food and Drug Administration (FDA) recommends that adults cons
Naya [18.7K]

The  individual can consume less than 184.6 g of the snack mix and still be within the FDA limit of salt consumption.

<h3>What is the mass of snack that can be consumed within the limit of sodium intake?</h3>

The mass of the snack mix that the individual can consume and still be within the FDA limit is calculated as follows:

U.S. Food and Drug Administration (FDA) recommends of sodium intake = less than 2.40 g of sodium per day.

Amount of salt in 100 g of snack mix = 1.30 g

Mass of snack that will contain 2.40 g of sodium = 2.40 * 100g/1.30 = 184.6 g of snack mix

Therefore, the individual can consume less than 184.6 of the snack mix and still be within the FDA limit of salt consumption.

In conclusion, the FDA recommends that an individual take in less than 2.40 g of sodium per day from their diet.

Learn more about salts at: brainly.com/question/23463868

#SPJ1

7 0
1 year ago
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