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3 years ago

6

A alone can do a piece of work in 8 days . A and B together can finish the same work in 6 days .If B alone is doing the work , h

ow long will he take

1 answer:

DiKsa [7]3 years ago

6 0

Please let me know if this is the correct answer.

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Help plz ASAP for 20pts

Paul [167]

Answer:

Not sure if this is correct but this is what I found.

area of sector=74.84

radius = 8

angle of sector=?

74.84=1/2×8²×angle of sector

74.84=32 × angle of sector

74.84/32= angle of sector

2.33875=angle of sector

Step-by-step explanation:

Sorry if it is incorrect.

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The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

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3 years ago

Solve the compound inequality. 6 – x > 15 or 2x – 9 ≥ 3 A. x > 9 or x ≤ 6 B. x < 9 or x ≥ –6 C. x > –9 or x ≤ –6 D.

Vesnalui [34]

Answer:

Step-by-step explanation:

Solve the compound inequality. 6 – x > 15 or 2x – 9 ≥ 3 A. x > 9 or x ≤ 6 B. x < 9 or x ≥ –6 C. x > –9 or x ≤ –6 D. x < –9 or x ≥ 6

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