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Svetlanka [38]
3 years ago
8

What's the answer ii

Chemistry
2 answers:
olga2289 [7]3 years ago
5 0
It is filtration... I think.
finlep [7]3 years ago
4 0
He answer to what was is ii

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Read the descriptions below of two substances and an experiment on each. Decide whether the result of the experiment tells you t
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Sample A - mixture

Sample B- Mixture

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SO42- + 2Cr(OH)3 + 4OH- → + 2CrO42- + 3SO32- + 5H2O
gizmo_the_mogwai [7]

Answer:

Reduced species and oxidizing agent: sulfur in the form of sulfate.

Oxidized species and reducing agent: chromium in the form of chromous hydroxide.

Explanation:

Hello!

In this case, for the reaction:

SO_4^{2-} + 2Cr(OH)_3 + 4OH^- \rightarrow  2CrO_4^{2-} + 3SO_3^{2-} + 5H_2O

We can see that the oxidation states of sulfur and chromium change from +6 to +4 and +3 to +6 respectively; in such a way, since the oxidized species is the same reducing agent because it undergoes an increase in the oxidation state, we infer that chromium is it as it goes from +3 to +6.

Moreover, since the reduced species is the same oxidizing agent because it undergoes a decrease in the oxidation state, we infer that sulfur is it as it goes from +6 to +4.

Best regards!

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