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Troyanec [42]
2 years ago
12

 Given that ∠ABC ≅ ∠DBE, which statement must be true? ∠ABC ≅ ∠ABD ∠ABD ≅ ∠CBE ∠CBD ≅ ∠DBE ∠CBD ≅ ∠ABC ​

Mathematics
1 answer:
Doss [256]2 years ago
4 0

Answer:

ABD ~= CBE

Step-by-step explanation:

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9(m +5) - 3(m - 2) = 8m + 31
castortr0y [4]

Answer:

m=10

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
It takes Juwan exactly 35 minutes by car to get to his grandmother's the nearest parking area is 4 minute walk from her apartmen
liq [111]

It takes him 35 + 4 = 39 total minutes one way, so it would take him 39 x 2 = 78 minutes for 1 round trip.

convert 5 hours and 12 minutes into minutes: 1 hour = 60 minutes.

5 hours x 60 minutes = 300 minutes.

300 + 12 = 312 total minutes for the week.

Divide total minutes by minutes per round trip:

312 / 78 = 4 round trips total

4 0
2 years ago
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Assume that the mean length of a human pregnancy is 269 days. If​ 95% of all human pregnancies last between 249 and 289 ​days, w
o-na [289]

Answer:93% not sure

Step-by-step explanation:

7 0
2 years ago
3. Are these ratios equivalent? 35:28 and 10:8 *
attashe74 [19]

Reduce each ratio to its minimum expression to find if they are equal.

35:28

\begin{gathered} \frac{35}{28}=\frac{7\cdot5}{7\cdot4} \\ =\frac{5}{4} \end{gathered}

10:8

\begin{gathered} \frac{10}{8}=\frac{2\cdot5}{2\cdot4} \\ =\frac{5}{4} \end{gathered}

Since both ratios reduce to 5:4, they are equivalent.

Another way to check a:b is equivalent to c:d, is that a*d = b*c

In this case, this will be true if 35 times 8 is equal to 10 times 28:

\begin{gathered} 35\cdot8=280 \\ 10\cdot28=280 \end{gathered}

Since both products are equal, then the ratios are equivalent.

4 0
9 months ago
4. A classmate is having difficulty finding the measures of <BGE and <BDG in the diagram on the right. What mathematical a
Firlakuza [10]
Part 1) Find the measures of angle BGE
we know that
The inscribed angle measures half of the arc it comprises.
so
angle BGE=(1/2)*[arc EB]  

Part 2) Find the angle BDG
we know that
The measure of the external angle is the semi-difference of the arcs that it covers.
so
angle BDG=(1/2)*[arc GEB-arc GB]

8 0
3 years ago
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